How to resolve the algorithm 100 prisoners step by step in the Julia programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm 100 prisoners step by step in the Julia programming language

Table of Contents

Problem Statement

Show and compare the computed probabilities of success for the two strategies, here, on this page.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm 100 prisoners step by step in the Julia programming language

Overview:

The provided Julia code simulates a game played by prisoners and studies the effectiveness of two strategies: random play and optimal play.

Code Details:

1. Importing Libraries:

using Random, Formatting
  • Imports the Random library for generating random numbers.
  • Imports the Formatting library for formatting output values.

2. randomplay Function:

function randomplay(n, numprisoners=100)
   ...
end

This function simulates the game with a random play strategy.

Input Parameters:

  • n: Number of simulations to run.
  • numprisoners: Number of prisoners (default: 100).

Function Body:

  • Initializes pardoned (number of pardoned prisoners), indrawer (a shuffled deck of cards), and found (indicator if a prisoner finds their own card).
  • Runs n simulations.
  • Iterates through the prisoners in each simulation.
  • For each prisoner, randomly reveals half the cards in the shuffled deck.
  • If the prisoner's card is not revealed, sets found to true and breaks the loop.
  • If all prisoners fail to find their cards, adds 1 to pardoned.
  • Returns the percentage of simulations where at least one prisoner was pardoned.

3. optimalplay Function:

function optimalplay(n, numprisoners=100)
   ...
end

This function simulates the game with an optimal play strategy.

Function Body:

  • Similar to randomplay but uses an optimal strategy for revealing cards.
  • For each prisoner, starts revealing cards sequentially from their own card.
  • If the prisoner's card is found, sets found to true and breaks the loop.
  • Returns the percentage of simulations where at least one prisoner was pardoned.

4. Simulation Execution:

const N = 100_000
println("Simulation count: $N")
println("Random play wins: ", format(randomplay(N), precision=8), "% of simulations.")
println("Optimal play wins: ", format(optimalplay(N), precision=8), "% of simulations.")
  • Sets the simulation count to N.
  • Calls randomplay and optimalplay functions and prints the percentage of simulations where at least one prisoner was pardoned for each strategy.

Source code in the julia programming language

using Random, Formatting

function randomplay(n, numprisoners=100)
    pardoned, indrawer, found = 0, collect(1:numprisoners), false
    for i in 1:n
        shuffle!(indrawer)
        for prisoner in 1:numprisoners
            found = false
            for reveal in randperm(numprisoners)[1:div(numprisoners, 2)]
                indrawer[reveal] == prisoner && (found = true) && break
            end
            !found && break
        end
        found && (pardoned += 1)
    end
    return 100.0 * pardoned / n
end

function optimalplay(n, numprisoners=100)
    pardoned, indrawer, found = 0, collect(1:numprisoners), false
    for i in 1:n
        shuffle!(indrawer)
        for prisoner in 1:numprisoners
            reveal = prisoner
            found = false
            for j in 1:div(numprisoners, 2)
                card = indrawer[reveal]
                card == prisoner && (found = true) && break
                reveal = card
            end
            !found && break
        end
        found && (pardoned += 1)
    end
    return 100.0 * pardoned / n
 end

const N = 100_000
println("Simulation count: $N")
println("Random play wins: ", format(randomplay(N), precision=8), "% of simulations.")
println("Optimal play wins: ", format(optimalplay(N), precision=8), "% of simulations.")


  

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