How to resolve the algorithm 15 puzzle game step by step in the Harbour programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm 15 puzzle game step by step in the Harbour programming language
Table of Contents
Problem Statement
Implement the Fifteen Puzzle Game.
The 15-puzzle is also known as:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm 15 puzzle game step by step in the Harbour programming language
Source code in the harbour programming language
#include "inkey.ch"
#include "Box.ch"
procedure Main()
// console init
SET SCOREBOARD OFF
SetMode(30,80)
ret := 0
// main loop
yn := .F.
DO WHILE yn == .F.
// draw console
cls
@ 0, 0 TO MaxRow(), MaxCol() DOUBLE
SetColor("BG+/B,W/N")
@ 0, 4 SAY " Slidng puzzle game "
SetColor()
// input size of grid
tam := 0
@ MaxRow() - 2, 4 SAY "Size of grid: " GET tam PICTURE "9"
READ
// Initialize numbers
lista := ARRAY (tam * tam)
FOR z := 1 TO tam * tam
lista[z] := z
NEXT
lista1 := lista
grid := ARRAY (tam,tam)
// populate grid with numbers
FOR i := 1 TO tam
FOR j := 1 TO tam
grid[i,j] := lista1[ (i-1) * tam + j]
NEXT
NEXT
Mostra(@grid)
InKey(0)
// initialize the game
n := 0
t := 0
lista := lista1 // lista for scrambling, lista1 preserve numbers in order
DO WHILE .T.
// scrambling numbers
FOR i := 1 TO tam*tam
n := Int ( ft_Rand1(tam * tam - 1) + 1 )
t := lista[n]
lista[n] := lista[i]
lista[i] := t
NEXT
// have solution?
possp := 0
invct := 0 // change counter
FOR i := 1 TO tam * tam -1
IF lista[i] != tam*tam
FOR j := i + 1 TO tam * tam
IF lista[j] != tam*tam
IF lista[i] > lista[j]
invct++
ENDIF
ENDIF
NEXT
ELSE
possp := i
ENDIF
NEXT
linv := If( ( (invct % 2) == 0 ), .T., .F.)
lkin := If( ( (tam - Int( (possp -1) / tam )) % 2) == 0, .T., .F. )
IF ( (tam % 2) != 0) // if grid size is odd
IF linv // if number of positions changes is even, solvable
EXIT
ELSE
LOOP // if is odd, not solvable, scramble more
ENDIF // if grid size is even
ELSE
// If changes is even and space position is in odd line
// or changes is odd and space position is in even line
// (XOR condition) is solvable
IF (linv .AND. !lkin) .OR. (!linv .AND. lkin) // XOR !!!
EXIT
ElSE // else scramble more
LOOP
ENDIF
ENDIF
ENDDO
// populate the grid with scrambled numbers
FOR i := 1 TO tam
FOR j := 1 TO tam
grid[i,j] := lista[ (i-1) * tam + j]
NEXT
NEXT
ret := Mostra(@grid)
// play
key := 0
DO WHILE LastKey() != K_ESC
key := 0
// find the space coords
xe := 0
ye := 0
lv := tam*tam
FOR i := 1 TO tam
FOR j := 1 TO tam
IF grid[i,j] == lv
xe :=i
ye :=j
ENDIF
NEXT
NEXT
// the direction keys
key := inkey(0)
DO CASE
CASE key == K_UP
IF xe > 1
grid[xe,ye] := grid[xe-1,ye]
grid[xe-1,ye] := lv
ENDIF
ret := Mostra(@grid)
CASE key == K_DOWN
IF xe < tam
grid[xe,ye] := grid[xe+1,ye]
grid[xe+1,ye] := lv
ENDIF
ret := Mostra(@grid)
CASE key == K_LEFT
IF ye > 1
grid[xe,ye] := grid[xe,ye-1]
grid[xe,ye-1] := lv
ENDIF
ret := Mostra(@grid)
CASE key == K_RIGHT
IF ye < tam
grid[xe,ye] := grid[xe,ye+1]
grid[xe,ye+1] := lv
ENDIF
ret := Mostra(@grid)
ENDCASE
IF ret == tam*tam-1 // ret is qtty numbers in position
@ MaxRow() - 3, 4 SAY "Fim de jogo!" // if ret == (size*size) -1
key := K_ESC // all numbers in position
EXIT // game solved
ENDIF
ENDDO
@ MaxRow() - 2, 4 SAY "Deseja sair? (yn): " GET yn PICTURE "Y"
READ
@ MaxRow() - 3, 4 SAY " "
ENDDO
return NIL
FUNCTION Mostra(grid)
// Show the gris
fim := 0 // how many numbers in position?
SetColor("BG+/B,W/N")
@ 5,10 , 5 + tam * 2, 9 + tam * 4 BOX B_SINGLE + Space(1)
i := 0
FOR y := 1 TO tam
FOR x := 1 TO tam
IF grid[x,y] == tam * tam // show space
SetColor(" B/GR+, W/N")
@ x*2 + 4, i + 11 SAY " "
SetColor("BG+/B,W/N")
ELSE
IF ( (x-1) * tam + y ) == grid[x,y] // show number in position
SetColor("W/G,W/N")
@ x*2 + 4, i + 11 SAY grid[x,y] PICTURE "99"
fim++
ELSE // show number out position
SetColor("BG+/B,W/N")
@ x*2 + 4, i + 11 SAY grid[x,y] PICTURE "99"
ENDIF
ENDIF
NEXT
i = i + 4
NEXT
SetColor(" W/N, BG+/B")
RETURN fim
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