How to resolve the algorithm 21 game step by step in the Wren programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm 21 game step by step in the Wren programming language
Table of Contents
Problem Statement
21 is a two player game, the game is played by choosing a number (1, 2, or 3) to be added to the running total. The game is won by the player whose chosen number causes the running total to reach exactly 21. The running total starts at zero. One player will be the computer. Players alternate supplying a number to be added to the running total.
Write a computer program that will:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm 21 game step by step in the Wren programming language
Source code in the wren programming language
import "./fmt" for Conv
import "./ioutil" for Input
import "random" for Random
var total = 0
var quit = false
var getChoice = Fn.new {
while (true) {
var input = Input.integer("Your choice 1 to 3: ", 0, 3)
if (input == 0) {
quit = true
return
}
var newTotal = total + input
if (newTotal > 21) {
System.print("Too big, try again")
} else {
total = newTotal
System.print("Running total is now %(total)")
return
}
}
}
var rand = Random.new()
var computer = Conv.itob(rand.int(2))
System.print("Enter 0 to quit at any time\n")
if (computer) {
System.print("The computer will choose first")
} else {
System.print("You will choose first")
}
System.print("\nRunning total is now 0\n")
var round = 1
while (true) {
System.print("ROUND %(round):\n")
for (i in 0..1) {
if (computer) {
var choice = (total < 18) ? 1 + rand.int(3) : 21 - total
total = total + choice
System.print("The computer chooses %(choice)")
System.print("Running total is now %(total)")
if (total == 21) {
System.print("\nSo, commiserations, the computer has won!")
return
}
} else {
getChoice.call()
if (quit) {
System.print("OK, quitting the game")
return
}
if (total == 21) {
System.print("\nSo, congratulations, you've won!")
return
}
}
System.print()
computer = !computer
}
round = round + 1
}
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