How to resolve the algorithm 99 bottles of beer step by step in the CoffeeScript programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm 99 bottles of beer step by step in the CoffeeScript programming language
Table of Contents
Problem Statement
Display the complete lyrics for the song: 99 Bottles of Beer on the Wall.
The lyrics follow this form: ... and so on, until reaching 0 (zero). Grammatical support for 1 bottle of beer is optional. As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the CoffeeScript programming language
Source code in the coffeescript programming language
bottlesOfBeer = (n) ->
"#{n} bottle#{if n is 1 then '' else 's'} of beer"
console.log """
#{bottlesOfBeer n} on the wall
#{bottlesOfBeer n}
Take one down, pass it around
#{bottlesOfBeer n - 1} on the wall
\n""" for n in [99..1]
for j in [99..1]
x=''
x += [j,j-1,'\nTake one down, pass it around\n'," bottles of beer",' on the wall\n'][i] for i in [0,3,4,0,3,2,1,3,4]
console.log x.replace /(1.+)s/g, '$1'
console.log( if (j+2)%4 then (x=Math.round j/4)+" bottle#{if x-1 then 's' else ''} of beer#{if (j+1)%4 then ' on the wall' else ''}" else "Take one down, pass it around" ) for j in [396..1]
((console.log if i is 2 then "Take one down, pass it around" else "#{b-!(i-1%4)} bottle#{if 4*b+i<10 and b-i then '' else 's'} of beer#{if i%3 then ' on the wall' else ''}") for i in [4..1]) for b in [99..1]
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