How to resolve the algorithm 99 bottles of beer step by step in the Genie programming language

Published on 12 May 2024 09:40 PM
#Genie

How to resolve the algorithm 99 bottles of beer step by step in the Genie programming language

Table of Contents

Problem Statement

Display the complete lyrics for the song:     99 Bottles of Beer on the Wall.

The lyrics follow this form: ... and so on, until reaching   0     (zero). Grammatical support for   1 bottle of beer   is optional. As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).

Let's start with the solution:

Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the Genie programming language

Source code in the genie programming language

[indent=4]
def plural(n:uint):string
    return (n == 1) ? "" : "s"
def no(n:uint):string
    return (n == 0) ? "No" : n.to_string()
init
    bottles:uint = 99;
    do
        print "%u bottle%s of beer on the wall", bottles, plural(bottles)
        print "%u bottle%s of beer", bottles, plural(bottles)
        print "Take one down, pass it around"
        --bottles
        print "%s bottle%s of beer on the wall\n", no(bottles), plural(bottles)
    while bottles != 0

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