Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the Julia programming language

Both code snippets implement the classic "99 bottles of beer on the wall" song in Julia.

The first one is a simple loop that prints the lyrics for each bottle count from 99 down to 1. The second one uses a more concise syntax with string interpolation and a ternary operator to determine the correct lyrics for each bottle count.

for i = 99:-1:1
   println(
       """
       $i bottles of beer on the wall
       $i bottles of beer
       Take one down, pass it around
       $(i - 1) bottles of beer on the wall
       """
   )
end

In the first code snippet, we use a for loop to iterate through the bottle counts from 99 down to 1. We then use the println function to print the lyrics for each bottle count.

bottles(n) = n == 0 ? "No more bottles" :
            n == 1 ? "1 bottle" :
            "$n bottles"

for n = 99:-1:1
   println("""
       $(bottles(n)) of beer on the wall
       $(bottles(n)) of beer
       Take one down, pass it around
       $(bottles(n - 1)) of beer on the wall
   """)
end

In the second code snippet, we define a bottles function to determine the correct lyrics for each bottle count. We then use a for loop to iterate through the bottle counts from 99 down to 1. We use string interpolation to embed the results of the bottles function into the lyrics.

bottles(n) = "$(n == 0 ? "No more" : n) bottle$(n == 1 ? "" : "s")"

for n = 99:-1:1
   println("""
       $(bottles(n)) of beer on the wall
       $(bottles(n)) of beer
       Take one down, pass it around
       $(bottles(n - 1)) of beer on the wall
   """)
end

In both code snippets, we use the ternary operator to determine the correct lyrics for each bottle count. The ternary operator is a shorthand way of writing an if-else statement. For example, the following code snippet is equivalent to the ternary operator in the first code snippet:

if n == 0
   lyrics = "No more bottles"
else
   lyrics = "$n bottles"
end

for i = 99:-1:1 print("\n$i bottles of beer on the wall\n$i bottles of beer\nTake one down, pass it around\n$(i-1) bottles of beer on the wall\n") end

bottles(n) = n==0 ? "No more bottles" :
             n==1 ? "1 bottle" :
             "$n bottles"

for n = 99:-1:1
    println("""
        $(bottles(n)) of beer on the wall
        $(bottles(n)) of beer
        Take one down, pass it around
        $(bottles(n-1)) of beer on the wall
    """)
end

bottles(n) = "$(n==0 ? "No more" : n) bottle$(n==1 ? "" : "s")"