How to resolve the algorithm 99 bottles of beer step by step in the MOO programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm 99 bottles of beer step by step in the MOO programming language
Table of Contents
Problem Statement
Display the complete lyrics for the song: 99 Bottles of Beer on the Wall.
The lyrics follow this form: ... and so on, until reaching 0 (zero). Grammatical support for 1 bottle of beer is optional. As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the MOO programming language
Source code in the moo programming language
bottles = 99;
while (bottles > 0)
unit = (bottles == 1 ? "bottle" | "bottles");
player:tell(bottles, " ", unit, " of beer on the wall.");
player:tell(bottles, " ", unit, " of beer.");
player:tell("Take one down, pass it around.");
bottles = bottles - 1;
endwhile
player:tell("0 bottles of beer on the wall.");
You may also check:How to resolve the algorithm Almost prime step by step in the Kotlin programming language
You may also check:How to resolve the algorithm Smarandache-Wellin primes step by step in the Phix programming language
You may also check:How to resolve the algorithm Strong and weak primes step by step in the Sidef programming language
You may also check:How to resolve the algorithm Best shuffle step by step in the Raku programming language
You may also check:How to resolve the algorithm Character codes step by step in the Lang5 programming language