How to resolve the algorithm 99 bottles of beer step by step in the Odin programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm 99 bottles of beer step by step in the Odin programming language

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Problem Statement

Display the complete lyrics for the song:     99 Bottles of Beer on the Wall.

The lyrics follow this form: ... and so on, until reaching   0     (zero). Grammatical support for   1 bottle of beer   is optional. As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).

Let's start with the solution:

Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the Odin programming language

Source code in the odin programming language

package main

import "core:fmt"
printf :: fmt.printf //Give fn on right an arbitrary name, or 9x fmt.printf("...")

bob :: proc( n: int , x: int){
	for i := x; i > 0 ; i -=1 {
		if      n >= 2		do printf("%d bottles of beer",n)
		else if n == 1 		do printf("1 bottle of beer")
		else if n == 0 		do printf("No more bottles of beer")

		if i == 1 	do printf(".\n")
		if i > 1 	do printf(" on the wall.\n")
		if i > 2 	do printf("\n")
	}
}

main :: proc(){
	n := 99
	bob(n, 2)
	for i := n - 1 ; i >= 0 ; i -= 1 {
		printf("Take one down; pass it around.\n")
		bob(i, 3)
	}
	printf ("Go to the store and buy some more.\n")
	printf ("%i bottles of beer on the wall.\n",n)
}

  

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