How to resolve the algorithm A+B step by step in the CoffeeScript programming language

Published on 12 May 2024 09:40 PM
#Coffeescript

How to resolve the algorithm A+B step by step in the CoffeeScript programming language

Table of Contents

Problem Statement

A+B   ─── a classic problem in programming contests,   it's given so contestants can gain familiarity with the online judging system being used.

Given two integers,   A and B. Their sum needs to be calculated.

Two integers are written in the input stream, separated by space(s):

The required output is one integer:   the sum of A and B.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm A+B step by step in the CoffeeScript programming language

Source code in the coffeescript programming language

<html>
<script type="text/javascript" src="http://jashkenas.github.com/coffee-script/extras/coffee-script.js"></script>
<script type="text/coffeescript">
a = window.prompt 'enter A number', ''
b = window.prompt 'enter B number', ''
document.getElementById('input').innerHTML = a + ' ' + b
sum = parseInt(a) + parseInt(b)
document.getElementById('output').innerHTML = sum
</script>
<body>
<div id='input'></div>
<div id='output'></div>
</body>
</html>

{ stdin } = process
sum = ( a, b ) -> a + b

display = ( messages... ) -> console.log messages...

parse = ( input ) ->
    parseInt x for x in ( x.trim() for x in input.split ' ' ) when x?.length

check = ( numbers... ) ->
    return no for x in numbers when isNaN x
    return no for x in numbers when not ( -1000 < x < 1000 )
    yes

prompt = ->
    display 'Please enter two integers between -1000 and 1000, separated by a space:'
    stdin.once 'data', ( data ) ->
        [ a, b ] = parse data
        if check a, b
            display "#{ a } + #{ b } = #{ sum a, b }"
        else
            display "Invalid input: #{ a }, #{ b }"
        do prompt
        return

# Resume input and set the incoming encoding.
stdin.resume()
stdin.setEncoding 'utf8'

# Start the main loop.
do prompt

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