Problem Statement

These define three classifications of positive integers based on their   proper divisors. Let   P(n)   be the sum of the proper divisors of   n   where the proper divisors are all positive divisors of   n   other than   n   itself.

6   has proper divisors of   1,   2,   and   3. 1 + 2 + 3 = 6,   so   6   is classed as a perfect number.

Calculate how many of the integers   1   to   20,000   (inclusive) are in each of the three classes. Show the results here.

Let's start with the solution:

func propdivsum(n) { n.sigma - n }

var h = Hash()
{|i| ++(h{propdivsum(i) <=> i} := 0) } << 1..20000
say "Perfect: #{h{0}}    Deficient: #{h{-1}}    Abundant: #{h{1}}"