How to resolve the algorithm Algebraic data types step by step in the jq programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Algebraic data types step by step in the jq programming language
Table of Contents
Problem Statement
Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
As an example, implement insertion in a red-black-tree. A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Red-Black Trees in a Functional Setting
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Algebraic data types step by step in the jq programming language
Source code in the jq programming language
# bindings($x) attempts to match . and $x structurally on the
# assumption that . is free of JSON objects, and that any objects in
# $x will have distinct, singleton keys that are to be interpreted as
# variables. These variables will match the corresponding entities in
# . if . and $x can be structurally matched.
#
# If . and $x cannot be matched, then null is returned;
# otherwise, if $x contains no objects, {} is returned;
# finally, if . and $x can be structurally matched, a composite object containing the bindings
# will be returned.
# Output: null (failure to match) or a single JSON object giving the bindings if any.
def bindings($x):
if $x == . then {} # by assumption, no bindings are necessary
elif ($x|type) == "object"
then ($x|keys) as $keys
| if ($keys|length) == 1 then {($keys[0]): .} else "objects should be singletons"|error end
elif type != ($x|type) then null
elif type == "array"
then if length != ($x|length) then null
else . as $in
| reduce range(0;length) as $i ({};
if . == null then null
else ($in[$i] | bindings($x[$i]) ) as $m
| if $m == null then null else . + $m end
end)
end
else null
end ;
include "bindings" {search: "."};
def E: []; # the empty node
# Each nonempty node is an array: [Color, Left, Value, Right]
# where Left and Right are nodes.
def B: "⚫";
def R: "🔴";
def b(x): bindings({} | x) // empty;
# Input: [$color, $left, $value, $right]
def balance:
def node: [R, [B, .a, .x, .b], .y, [B, .c, .z, .d]];
( b([B, [R, [R, {a}, {x}, {x}], {y}, {c}], {z}, {d}])
// b([B, [R, {a}, {x}, [R, {b}, {y}, {c}]], {z}, {d}])
// b([B, {a},{x}, [R, [R, {b}, {y}, {c}], {z}, {d}]])
// b([B, {a},{x}, [R, {b}, {y}, [R, {c}, {z}, {d}]]])
| node) // . ;
# Input: a node
def ins($x):
if . == E then [R, E, $x, E]
else . as [$col, $left, $y, $right]
| if $x < $y then [ $col, ($left|ins($x)), $y, $right] | balance
elif $x > $y then [ $col, $left, $y, ($right|ins($x)) ] | balance
else $left
end
end;
# insert(Value) into .
def insert($x):
ins($x) as [$col, $left, $y, $right]
| [ B, $left, $y, $right] ;
def pp: walk( if type == "array" then map(select(length>0)) else . end);
def task($n):
reduce range(0; $n) as $i (E; insert($i));
task(16) | pp
jq -n -f pattern-matching.jq | grep -v '[][]' | tr -d ',"'
You may also check:How to resolve the algorithm Determine if a string is numeric step by step in the CoffeeScript programming language
You may also check:How to resolve the algorithm Function prototype step by step in the Wren programming language
You may also check:How to resolve the algorithm Ackermann function step by step in the Arturo programming language
You may also check:How to resolve the algorithm Loops/Break step by step in the Oberon-2 programming language
You may also check:How to resolve the algorithm Character codes step by step in the Oberon-2 programming language