How to resolve the algorithm Anagrams/Deranged anagrams step by step in the Picat programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Anagrams/Deranged anagrams step by step in the Picat programming language
Table of Contents
Problem Statement
Two or more words are said to be anagrams if they have the same characters, but in a different order. By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words. Use the word list at unixdict to find and display the longest deranged anagram.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Anagrams/Deranged anagrams step by step in the Picat programming language
Source code in the picat programming language
go =>
M = [W:W in read_file_lines("unixdict.txt")].group(sort),
Deranged = [Value : _Key=Value in M, Value.length > 1, allderanged(Value)],
MaxLen = max([V[1].length : V in Deranged]),
println([V : V in Deranged, V[1].length==MaxLen]),
nl.
% A and B are deranged: i.e. there is no
% position with the same character.
deranged(A,B) =>
foreach(I in 1..A.length)
A[I] != B[I]
end.
% All words in list Value are deranged anagrams of each other.
allderanged(Value) =>
IsDeranged = 1,
foreach(V1 in Value, V2 in Value, V1 @< V2, IsDeranged = 1)
if not deranged(V1,V2) then
IsDeranged := 0
end
end,
IsDeranged == 1.
% Groups the element in List according to the function F
group(List, F) = P, list(List) =>
P = new_map(),
foreach(E in List)
V = apply(F,E),
P.put(V, P.get(V,[]) ++ [E])
end.
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