How to resolve the algorithm Anagrams step by step in the E programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Anagrams step by step in the E programming language
Table of Contents
Problem Statement
When two or more words are composed of the same characters, but in a different order, they are called anagrams. Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Anagrams step by step in the E programming language
Source code in the e programming language
println("Downloading...")
when (def wordText := <- getText()) -> {
def words := wordText.split("\n")
def storage := [].asMap().diverge()
def anagramTable extends storage {
to get(key) { return storage.fetch(key, fn { storage[key] := [].diverge() }) }
}
println("Grouping...")
var largestGroupSeen := 0
for word in words {
def anagramGroup := anagramTable[word.sort()]
anagramGroup.push(word)
largestGroupSeen max= anagramGroup.size()
}
println("Selecting...")
for _ => anagramGroup ? (anagramGroup.size() == mostSeen) in anagramTable {
println(anagramGroup.snapshot())
}
}
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