How to resolve the algorithm Anagrams step by step in the E programming language

Published on 12 May 2024 09:40 PM
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How to resolve the algorithm Anagrams step by step in the E programming language

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Problem Statement

When two or more words are composed of the same characters, but in a different order, they are called anagrams. Using the word list at   http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Anagrams step by step in the E programming language

Source code in the e programming language

println("Downloading...")
when (def wordText :=  <- getText()) -> {
    def words := wordText.split("\n")

    def storage := [].asMap().diverge()
    def anagramTable extends storage {
        to get(key) { return storage.fetch(key, fn { storage[key] := [].diverge() }) }
    }

    println("Grouping...")
    var largestGroupSeen := 0
    for word in words {
        def anagramGroup := anagramTable[word.sort()]
        anagramGroup.push(word)
        largestGroupSeen max= anagramGroup.size()
    }

    println("Selecting...")
    for _ => anagramGroup ? (anagramGroup.size() == mostSeen) in anagramTable {
        println(anagramGroup.snapshot())
    }
}

  

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