How to resolve the algorithm Anagrams step by step in the Go programming language
How to resolve the algorithm Anagrams step by step in the Go programming language
Table of Contents
Problem Statement
When two or more words are composed of the same characters, but in a different order, they are called anagrams. Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Anagrams step by step in the Go programming language
The provided Go program finds and prints all the words in a given text file that have the most unique characters.
A step-by-step explanation of the program:
-
http.Get
: It retrieves the content of a file from a URL. In this case, it fetchesunixdict.txt
fromwiki.puzzlers.org
. -
ioutil.ReadAll
: It reads the content of the HTTP response body into a byte sliceb
. -
bs
: It defines a custom typebyteSlice
that implements thesort.Interface
interface for sorting byte slices. This type is used to sort the characters of each word alphabetically. -
m
: It creates a mapm
that maps a sorted character sequence to a slice of words that have that character sequence. -
for
Loop:- It iterates over the bytes in
b
and constructs a newbyteSlice
bs
for each word. - It sorts
bs
and converts it back to a stringk
. - It checks if there are any words mapped to
k
in them
map. If not, it appends a new slicea
tom[k]
. Otherwise, it appends the word to the existinga
slice. - It keeps track of the maximum number of words (
ma
) that have the most unique characters.
- It iterates over the bytes in
-
After processing all the words, it iterates through the values of
m
and prints the words that have the maximum number of unique characters.
In summary, this program takes a text file, finds all the words that have the most unique characters, and prints those words. The custom byteSlice
type and the sorting of character sequences are used to efficiently determine which words have the most unique characters.
Source code in the go programming language
package main
import (
"bytes"
"fmt"
"io/ioutil"
"net/http"
"sort"
)
func main() {
r, err := http.Get("http://wiki.puzzlers.org/pub/wordlists/unixdict.txt")
if err != nil {
fmt.Println(err)
return
}
b, err := ioutil.ReadAll(r.Body)
r.Body.Close()
if err != nil {
fmt.Println(err)
return
}
var ma int
var bs byteSlice
m := make(map[string][][]byte)
for _, word := range bytes.Fields(b) {
bs = append(bs[:0], byteSlice(word)...)
sort.Sort(bs)
k := string(bs)
a := append(m[k], word)
if len(a) > ma {
ma = len(a)
}
m[k] = a
}
for _, a := range m {
if len(a) == ma {
fmt.Printf("%s\n", a)
}
}
}
type byteSlice []byte
func (b byteSlice) Len() int { return len(b) }
func (b byteSlice) Swap(i, j int) { b[i], b[j] = b[j], b[i] }
func (b byteSlice) Less(i, j int) bool { return b[i] < b[j] }
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