How to resolve the algorithm Anagrams step by step in the OCaml programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Anagrams step by step in the OCaml programming language
Table of Contents
Problem Statement
When two or more words are composed of the same characters, but in a different order, they are called anagrams. Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Anagrams step by step in the OCaml programming language
Source code in the ocaml programming language
let explode str =
let l = ref [] in
let n = String.length str in
for i = n - 1 downto 0 do
l := str.[i] :: !l
done;
(!l)
let implode li =
let n = List.length li in
let s = String.create n in
let i = ref 0 in
List.iter (fun c -> s.[!i] <- c; incr i) li;
(s)
let () =
let h = Hashtbl.create 3571 in
let ic = open_in "unixdict.txt" in
try while true do
let w = input_line ic in
let k = implode (List.sort compare (explode w)) in
let l =
try Hashtbl.find h k
with Not_found -> []
in
Hashtbl.replace h k (w::l);
done with End_of_file -> ();
let n = Hashtbl.fold (fun _ lw n -> max n (List.length lw)) h 0 in
Hashtbl.iter (fun _ lw ->
if List.length lw >= n then
( List.iter (Printf.printf " %s") lw;
print_newline () )
) h
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