How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Clojure programming language

Published on 12 May 2024 09:40 PM
#Clojure

How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Clojure programming language

Table of Contents

Problem Statement

Using the in-built capabilities of your language, calculate the integer value of:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Clojure programming language

Source code in the clojure programming language

(defn exp [n k] (reduce * (repeat k n)))

(def big (->> 2 (exp 3) (exp 4) (exp 5)))
(def sbig (str big))

(assert (= "62060698786608744707" (.substring sbig 0 20)))
(assert (= "92256259918212890625" (.substring sbig (- (count sbig) 20))))
(println (count sbig) "digits")

(println (str (.substring sbig 0 20) ".."
	      (.substring sbig (- (count sbig) 20)))
	 (str "(" (count sbig) " digits)"))


(defn exp [n k]
  (cond
    (zero? (mod k 2)) (recur (* n n) (/ k 2))
    (zero? (mod k 3)) (recur (* n n n) (/ k 3))
    :else (reduce * (repeat k n))))

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