Source code in the nanoquery programming language

value = str(5^(4^(3^2)))

first20 = value.substring(0,20)
last20 = value.substring(len(value) - 20)

println "The first twenty digits are " + first20
println "The last twenty digits are " + last20

if (first20 = "62060698786608744707") && (last20 = "92256259918212890625")
	println "\nThese digits are correct.\n"
end

println "The result is " + len(str(value)) + " digits long"