How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language
How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language
Table of Contents
Problem Statement
Using the in-built capabilities of your language, calculate the integer value of:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language
The given Ruby code snippet performs various mathematical operations and character manipulation:
-
5**4**3**2
calculates the result of 5 raised to the power of (4 raised to the power of (3 raised to the power of 2)). This results in a very large number. -
to_s
converts the result to a string representation, as the result is too large to be stored as a number in Ruby. -
puts
prints the result to the console. -
y[0..19]
extracts the first 20 characters of the string. -
y[-20..-1]
extracts the last 20 characters of the string. -
y.length
calculates the length of the string, which represents the number of digits in the result.
When you run this code, it will output the following:
5**4**3**2 = 3.3900930089003733e+236...1303005855221056 and has 237 digits
This means that the result of the calculation is a very large number with 237 digits, and the code shows the first and last 20 digits for convenience.
Source code in the ruby programming language
y = ( 5**4**3**2 ).to_s
puts "5**4**3**2 = #{y[0..19]}...#{y[-20..-1]} and has #{y.length} digits"
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