How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language

Table of Contents

Problem Statement

Using the in-built capabilities of your language, calculate the integer value of:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Ruby programming language

The given Ruby code snippet performs various mathematical operations and character manipulation:

  1. 5**4**3**2 calculates the result of 5 raised to the power of (4 raised to the power of (3 raised to the power of 2)). This results in a very large number.

  2. to_s converts the result to a string representation, as the result is too large to be stored as a number in Ruby.

  3. puts prints the result to the console.

  4. y[0..19] extracts the first 20 characters of the string.

  5. y[-20..-1] extracts the last 20 characters of the string.

  6. y.length calculates the length of the string, which represents the number of digits in the result.

When you run this code, it will output the following:

5**4**3**2 = 3.3900930089003733e+236...1303005855221056 and has 237 digits

This means that the result of the calculation is a very large number with 237 digits, and the code shows the first and last 20 digits for convenience.

Source code in the ruby programming language

y = ( 5**4**3**2 ).to_s
puts "5**4**3**2 = #{y[0..19]}...#{y[-20..-1]} and has #{y.length} digits"


  

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