How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Rust programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Rust programming language
Table of Contents
Problem Statement
Using the in-built capabilities of your language, calculate the integer value of:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Arbitrary-precision integers (included) step by step in the Rust programming language
Source code in the rust programming language
extern crate num;
use num::bigint::BigUint;
use num::FromPrimitive;
use num::pow::pow;
fn main() {
let big = BigUint::from_u8(5).unwrap();
let answer_as_string = format!("{}", pow(big,pow(4,pow(3,2))));
// The rest is output formatting.
let first_twenty: String = answer_as_string.chars().take(20).collect();
let last_twenty_reversed: Vec<char> = answer_as_string.chars().rev().take(20).collect();
let last_twenty: String = last_twenty_reversed.into_iter().rev().collect();
println!("Number of digits: {}", answer_as_string.len());
println!("First and last digits: {:?}..{:?}", first_twenty, last_twenty);
}
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