How to resolve the algorithm Arithmetic numbers step by step in the FreeBASIC programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Arithmetic numbers step by step in the FreeBASIC programming language
Table of Contents
Problem Statement
A positive integer n is an arithmetic number if the average of its positive divisors is also an integer. Clearly all odd primes p must be arithmetic numbers because their only divisors are 1 and p whose sum is even and hence their average must be an integer. However, the prime number 2 is not an arithmetic number because the average of its divisors is 1.5. 30 is an arithmetic number because its 7 divisors are: [1, 2, 3, 5, 6, 10, 15, 30], their sum is 72 and average 9 which is an integer. Calculate and show here:
- The first 100 arithmetic numbers.
- The xth arithmetic number where x = 1,000 and x = 10,000.
- How many of the first x arithmetic numbers are composite. Note that, technically, the arithmetic number 1 is neither prime nor composite. Carry out the same exercise in 2. and 3. above for x = 100,000 and x = 1,000,000.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Arithmetic numbers step by step in the FreeBASIC programming language
Source code in the freebasic programming language
' Rosetta Code problem: https://rosettacode.org/wiki/Arithmetic_numbers
' by Jjuanhdez, 06/2022
Dim As Double t0 = Timer
Dim As Integer N = 1, ArithCnt = 0, CompCnt = 0
Dim As Integer Div, DivCnt, Sum, Quot
Print "The first 100 arithmetic numbers are:"
Do
Div = 1 : DivCnt = 0 : Sum = 0
Do
Quot = N / Div
If Quot < Div Then Exit Do
If Quot = Div AndAlso (N Mod Div) = 0 Then 'N is a square
Sum += Quot
DivCnt += 1
Exit Do
End If
If (N Mod Div) = 0 Then
Sum += Div + Quot
DivCnt += 2
End If
Div += 1
Loop
If (Sum Mod DivCnt) = 0 Then 'N is arithmetic
ArithCnt += 1
If ArithCnt <= 100 Then
Print Using "####"; N;
If (ArithCnt Mod 20) = 0 Then Print
End If
If DivCnt > 2 Then CompCnt += 1
Select Case ArithCnt
Case 1e3
Print Using !"\nThe #######th arithmetic number is #####,### up to which ###,### are composite."; ArithCnt; N; CompCnt
Case 1e4, 1e5, 1e6
Print Using "The #######th arithmetic number is #####,### up to which ###,### are composite."; ArithCnt; N; CompCnt
End Select
End If
N += 1
Loop Until ArithCnt >= 1e6
Print !"\nTook"; Timer - t0; " seconds on i5 @3.20 GHz"
Sleep
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