How to resolve the algorithm Arrays step by step in the Haskell programming language

Published on 7 June 2024 03:52 AM
#Haskell

How to resolve the algorithm Arrays step by step in the Haskell programming language

Table of Contents

Problem Statement

This task is about arrays. For hashes or associative arrays, please see Creating an Associative Array. For a definition and in-depth discussion of what an array is, see Array.

Show basic array syntax in your language. Basically, create an array, assign a value to it, and retrieve an element   (if available, show both fixed-length arrays and dynamic arrays, pushing a value into it). Please discuss at Village Pump:   Arrays.
Please merge code in from these obsolete tasks:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Arrays step by step in the Haskell programming language

In the given code, we use the Data.Array.IO module to create an IOArray, which is an array in Haskell that can be modified in IO actions. We create an array with the bounds (1,10) and initialize each element to 37 using the newArray function. We then use the readArray function to read the value at index 1, which will be 37. We then use the writeArray function to modify the value at index 1 to 64. Finally, we use the readArray function again to read the value at index 1, which will now be 64. We then print the values of a and b to the console. The output will be (37,64).

Source code in the haskell programming language

import Data.Array.IO

main = do arr <- newArray (1,10) 37 :: IO (IOArray Int Int)
          a <- readArray arr 1
          writeArray arr 1 64
          b <- readArray arr 1 
          print (a,b)

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