How to resolve the algorithm Arrays step by step in the jq programming language

Published on 12 May 2024 09:40 PM
#Jq

How to resolve the algorithm Arrays step by step in the jq programming language

Table of Contents

Problem Statement

This task is about arrays. For hashes or associative arrays, please see Creating an Associative Array. For a definition and in-depth discussion of what an array is, see Array.

Show basic array syntax in your language. Basically, create an array, assign a value to it, and retrieve an element   (if available, show both fixed-length arrays and dynamic arrays, pushing a value into it). Please discuss at Village Pump:   Arrays.
Please merge code in from these obsolete tasks:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Arrays step by step in the jq programming language

Source code in the jq programming language

# Create a new array with length 0
[]

# Create a new array of 5 nulls
[][4] = null   # setting the element at offset 4 expands the array

# Create an array having the elements 1 and 2 in that order 
[1,2]

# Create an array of integers from 0 to 10 inclusive
[ range(0; 11) ]

# If a is an array (of any length), update it so that a[2] is 5
a[2] = 5;

# Append arrays a and b
a + b

# Append an element, e, to an array a
a + [e]

##################################################
# In the following, a is assumed to be [0,1,2,3,4]

# It is not an error to use an out-of-range index:
a[10]  # => null

# Negative indices count backwards from after the last element:
a[-1]  # => 4

# jq supports simple slice operations but
# only in the forward direction:
a[:1]  # => [0]
a[1:]  # => [1,2,3,4]
a[2:4] # => [2,3]
a[4:2] # null

  

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