How to resolve the algorithm Ascending primes step by step in the ALGOL W programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Ascending primes step by step in the ALGOL W programming language
Table of Contents
Problem Statement
Generate and show all primes with strictly ascending decimal digits. Aside: Try solving without peeking at existing solutions. I had a weird idea for generating a prime sieve faster, which needless to say didn't pan out. The solution may be p(r)etty trivial but generating them quickly is at least mildly interesting. Tip: filtering all 7,027,260 primes below 123,456,789 probably won't kill you, but there is at least one significantly better and much faster way, needing a mere 511 odd/prime tests.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Ascending primes step by step in the ALGOL W programming language
Source code in the algol programming language
begin % find all primes with strictly ascending digits - translation of Lua %
% quicksorts v, the bounds of v must be specified in lb and ub %
procedure quicksort ( integer array v( * )
; integer value lb, ub
) ;
if ub > lb then begin
% more than one element, so must sort %
integer left, right, pivot;
left := lb;
right := ub;
% choosing the middle element of the array as the pivot %
pivot := v( left + ( ( right + 1 ) - left ) div 2 );
while begin
while left <= ub and v( left ) < pivot do left := left + 1;
while right >= lb and v( right ) > pivot do right := right - 1;
left <= right
end do begin
integer swap;
swap := v( left );
v( left ) := v( right );
v( right ) := swap;
left := left + 1;
right := right - 1
end while_left_le_right ;
quicksort( v, lb, right );
quicksort( v, left, ub )
end quicksort ;
% returns true if n is prime, false otherwise %
logical procedure is_prime( integer value n ) ;
if n < 2 then false
else if n rem 2 = 0 then n = 2
else if n rem 3 = 0 then n = 3
else begin
logical prime; prime := true;
for f := 5 step 6 until entier( sqrt( n ) ) do begin
if n rem f = 0 or n rem ( f + 2 ) = 0 then begin
prime := false;
goto done
end if_n_rem_f_eq_0_or_n_rem_f_plus_2_eq_0
end for_f;
done: prime
end is_prime ;
% increments n and also returns its new value %
integer procedure inc ( integer value result n ) ; begin n := n + 1; n end;
% sets primes to the list of ascending primes and lenPrimes to the %
% number of ascending primes - primes must be big enough, e.g. have 511 %
% elements %
procedure ascending_primes ( integer array primes ( * )
; integer result lenPrimes
) ;
begin
integer array digits ( 1 :: 9 );
integer array candidates ( 1 :: 6000 );
integer lenCandidates;
candidates( 1 ) := 0;
lenCandidates := 1;
lenPrimes := 0;
for i := 1 until 9 do digits( i ) := i;
for i := 1 until 9 do begin
for j := 1 until lenCandidates do begin
integer cValue; cValue := candidates( j ) * 10 + digits( i );
if is_prime( cValue ) then primes( inc( lenPrimes ) ) := cValue;
candidates( inc( lenCandidates ) ) := cValue
end for_j
end for_i ;
quickSort( primes, 1, lenPrimes );
end ascending_primes ;
begin % find the ascending primes and print them %
integer array primes ( 1 :: 512 );
integer lenPrimes;
ascending_primes( primes, lenPrimes );
for i := 1 until lenPrimes do begin
writeon( i_w := 8, s_w := 0, " ", primes( i ) );
if i rem 10 = 0 then write()
end for_i
end
end.
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