How to resolve the algorithm Assertions step by step in the jq programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Assertions step by step in the jq programming language
Table of Contents
Problem Statement
Assertions are a way of breaking out of code when there is an error or an unexpected input. Some languages throw exceptions and some treat it as a break point.
Show an assertion in your language by asserting that an integer variable is equal to 42.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Assertions step by step in the jq programming language
Source code in the jq programming language
def assert(exp; $msg):
def m: $msg | if type == "string" then . else [.[]] | join(":") end;
if env.JQ_ASSERT then
(exp as $e | if $e then . else . as $in | "assertion violation @ \(m) => \($e)" | debug | $in end)
else . end;
def assert(exp):
if env.JQ_ASSERT then
(exp as $e | if $e then . else . as $in | "assertion violation: \($e)" | debug | $in end)
else . end;
def asserteq(x;y;$msg):
def m: $msg | if type == "string" then . else [.[]] | join(":") end;
def s: (if $msg then m + ": " else "" end) + "\(x) != \(y)";
if env.JQ_ASSERT then
if x == y then .
else . as $in | "assertion violation @ \(s)" | debug | $in
end
else . end;
# File: example.jq
# This example assumes the availability of the $__loc__ function
# and that assert.jq is in the same directory as example.jq.
include "assert" {search: "."};
def test:
"This is an input"
| 0 as $x
| assert($x == 42; $__loc__),
asserteq($x; 42; $__loc__);
test
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