How to resolve the algorithm Assertions step by step in the jq programming language

Published on 12 May 2024 09:40 PM
#Jq

How to resolve the algorithm Assertions step by step in the jq programming language

Table of Contents

Problem Statement

Assertions are a way of breaking out of code when there is an error or an unexpected input. Some languages throw exceptions and some treat it as a break point.

Show an assertion in your language by asserting that an integer variable is equal to 42.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Assertions step by step in the jq programming language

Source code in the jq programming language

def assert(exp; $msg):
  def m: $msg | if type == "string" then . else [.[]] | join(":") end;
  if env.JQ_ASSERT then
    (exp as $e | if $e then . else . as $in | "assertion violation @ \(m) => \($e)" | debug | $in end)
  else . end;

def assert(exp):
  if env.JQ_ASSERT then
    (exp as $e | if $e then . else . as $in | "assertion violation: \($e)" | debug | $in end)
   else . end;

def asserteq(x;y;$msg):
  def m: $msg | if type == "string" then . else [.[]] | join(":") end;
  def s: (if $msg then m + ": " else "" end) + "\(x) != \(y)";
  if env.JQ_ASSERT then
     if x == y then .
     else . as $in | "assertion violation @ \(s)" | debug | $in
     end
   else . end;

# File: example.jq
# This example assumes the availability of the $__loc__ function
# and that assert.jq is in the same directory as example.jq.

include "assert" {search: "."};

def test:
  "This is an input"
  | 0 as $x
  | assert($x == 42; $__loc__),
    asserteq($x; 42; $__loc__);

test

  

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