How to resolve the algorithm Associative array/Iteration step by step in the Objective-C programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Associative array/Iteration step by step in the Objective-C programming language

Table of Contents

Problem Statement

Also show how to iterate just over the keys, or the values, if there is a separate way to do that in your language.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Associative array/Iteration step by step in the Objective-C programming language

Source code in the objective-c programming language

NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys:
                        [NSNumber numberWithInt:13], @"hello",
                        [NSNumber numberWithInt:31], @"world",
                        [NSNumber numberWithInt:71], @"!", nil];

// iterating over keys:
for (id key in myDict) {
    NSLog(@"key = %@", key);
}

// iterating over values:
for (id value in [myDict objectEnumerator]) {
    NSLog(@"value = %@", value);
}


NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys:
                        [NSNumber numberWithInt:13], @"hello",
                        [NSNumber numberWithInt:31], @"world",
                        [NSNumber numberWithInt:71], @"!", nil];

// iterating over keys:
NSEnumerator *enm = [myDict keyEnumerator];
id key;
while ((key = [enm nextObject])) {
    NSLog(@"key = %@", key);
}

// iterating over values:
enm = [myDict objectEnumerator];
id value;
while ((value = [enm nextObject])) {
    NSLog(@"value = %@", value);
}


NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys:
                        [NSNumber numberWithInt:13], @"hello",
                        [NSNumber numberWithInt:31], @"world",
                        [NSNumber numberWithInt:71], @"!", nil];

// iterating over keys and values:
[myDict enumerateKeysAndObjectsUsingBlock: ^(id key, id value, BOOL *stop) {
    NSLog(@"key = %@, value = %@", key, value);
}];


  

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