How to resolve the algorithm Babbage problem step by step in the Processing programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Babbage problem step by step in the Processing programming language

Table of Contents

Problem Statement

Charles Babbage, looking ahead to the sorts of problems his Analytical Engine would be able to solve, gave this example: He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.

The task is to find out if Babbage had the right answer — and to do so, as far as your language allows it, in code that Babbage himself would have been able to read and understand. As Babbage evidently solved the task with pencil and paper, a similar efficient solution is preferred. For these purposes, Charles Babbage may be taken to be an intelligent person, familiar with mathematics and with the idea of a computer; he has written the first drafts of simple computer programmes in tabular form. [Babbage Archive Series L].

The aim of the task is to write a program that is sufficiently clear and well-documented for such a person to be able to read it and be confident that it does indeed solve the specified problem.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Babbage problem step by step in the Processing programming language

Source code in the processing programming language

// Lines that begin with two slashes, thus, are comments: they
// will be ignored by the machine.

// First we must declare a variable, n, suitable to store an integer:

int n;

// Each statement we address to the machine must end with a semicolon.

// To begin with, the value of n will be zero:

n = 0;

// Now we must repeatedly increase it by one, checking each time to see
// whether its square ends in 269,696.

// We shall do this by seeing whether the remainder, when n squared
// is divided by one million, is equal to 269,696.

do {
    n = n + 1;
} while (n * n % 1000000 != 269696);

// To read this formula, it is necessary to know the following
// elements of the notation:
//     * means 'multiplied by'
//     % means 'modulo', or remainder after division
//     != means 'is not equal to'

// Now that we have our result, we need to display it.

// println is short for 'print line'

println(n);


  

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