How to resolve the algorithm Babbage problem step by step in the C++ programming language
How to resolve the algorithm Babbage problem step by step in the C++ programming language
Table of Contents
Problem Statement
Charles Babbage, looking ahead to the sorts of problems his Analytical Engine would be able to solve, gave this example: He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.
The task is to find out if Babbage had the right answer — and to do so, as far as your language allows it, in code that Babbage himself would have been able to read and understand. As Babbage evidently solved the task with pencil and paper, a similar efficient solution is preferred. For these purposes, Charles Babbage may be taken to be an intelligent person, familiar with mathematics and with the idea of a computer; he has written the first drafts of simple computer programmes in tabular form. [Babbage Archive Series L].
The aim of the task is to write a program that is sufficiently clear and well-documented for such a person to be able to read it and be confident that it does indeed solve the specified problem.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Babbage problem step by step in the C++ programming language
This C++ program appears to be designed to find a specific number whose square ends with the digits 269696. It does this by incrementing a variable current
and checking if the square of current
ends with the desired digits. Here's a step-by-step breakdown of the code:
-
int current = 0;
: Initializes an integer variable namedcurrent
to 0. This variable will be used to iterate through numbers and find the one whose square satisfies the given condition. -
while ((current * current) % 1000000 != 269696) { current++; }
: This is the main loop of the program, where it continues to incrementcurrent
until it finds a number whose square ends with 269696.(current * current)
: Calculates the square of the current number.(current * current) % 1000000
: Takes the last six digits of the square.!= 269696
: Checks if the last six digits are not equal to 269696.current++
: If the condition is not met, incrementscurrent
by 1.
-
std::cout << "The square of " << current << " is " << (current * current) << "!";
: Once the loop finds a number that meets the condition, this line prints a message to the console.std::cout << ...
: Prints the specified text and values to the console.current
: Prints the value ofcurrent
.(current * current)
: Calculates and prints the square ofcurrent
.
-
return 0;
: Indicates the end of themain
function and the program's successful execution.
Source code in the cpp programming language
#include <iostream>
int main( ) {
int current = 0 ;
while ( ( current * current ) % 1000000 != 269696 )
current++ ;
std::cout << "The square of " << current << " is " << (current * current) << " !\n" ;
return 0 ;
}
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