How to resolve the algorithm Balanced brackets step by step in the M2000 Interpreter programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Balanced brackets step by step in the M2000 Interpreter programming language

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Step by Step solution about How to resolve the algorithm Balanced brackets step by step in the M2000 Interpreter programming language

Source code in the m2000 programming language

module Balanced_brackets{
	// Generate a string with   N   opening brackets   [   and with   N   closing brackets   ],   in some arbitrary order.
	function randomBrackets(max as long) {
		if max<1 then max=1
		def putbracket()=mid$("[[[[]]",random(1,6),1)
		dim a(random(1, max)) as string<
		=a()#str$("")
	}
	// Determine whether the generated string is balanced; that is, whether it consists entirely of pairs of opening/closing brackets (in that order), none of which mis-nest.
	function check(s as string) {
		long i, level
		for i=1 to len(s)
		if mid$(s,i,1)="[" then level++ else level--
		if level<0 then exit for
		next
		=level=0
	}
	string k
	boolean m
	do
		k=randomBrackets(10)
		m=check(k)
		print k;@(12);":  ";if$(m->"OK", "NOT OK")
	until m
}
Balanced_brackets

  

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