How to resolve the algorithm Best shuffle step by step in the Ruby programming language
How to resolve the algorithm Best shuffle step by step in the Ruby programming language
Table of Contents
Problem Statement
Shuffle the characters of a string in such a way that as many of the character values are in a different position as possible. A shuffle that produces a randomized result among the best choices is to be preferred. A deterministic approach that produces the same sequence every time is acceptable as an alternative. Display the result as follows: The score gives the number of positions whose character value did not change.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Best shuffle step by step in the Ruby programming language
The provided Ruby code defines a method called best_shuffle
that attempts to find the best possible shuffle of a given string s
while preserving the original character frequencies. It returns the shuffled string and a score indicating how many characters in the shuffled string are in the same position as in the original string.
Here's a detailed breakdown of the code:
-
Initialization:
- An empty array
pos
is created to store positions in the desired order for filling the shuffled string. - A hash
g
is created to group characters ins
by their positions. For example, ifs = "abracadabra"
, theng["a"] = [2, 4]
because characters at positions 2 and 4 are both 'a'.
- An empty array
-
Sorting:
- An array
k
is created by sorting the keys ofg
(i.e., the unique letters) in ascending order based on how many times each letter appears ins
.
- An array
-
Filling Positions:
- The code iterates through the sorted letters in
k
until all letters have been processed. - For each letter, it checks if its entry exists in
g
. If it does, it pushes the position of the first occurrence of that letter ins
onto thepos
array. - If the entry for the letter becomes empty (i.e., all positions for that letter have been filled), its key is deleted from
g
.
- The code iterates through the sorted letters in
-
Shuffling and Scoring:
- A copy of the input string
s
is created inletters
. - An empty string
new
of the same length ass
is created, initially filled with a placeholder character ('?'). - The code iterates through the positions in
pos
in reverse order. - For each position, it finds the first character in
letters
that is the same as the character at that position ins
. - The found character is placed in the corresponding position in
new
and is removed fromletters
.
- A copy of the input string
-
Scoring:
- Finally, the score is calculated by comparing
new
with the original strings
, counting the number of character matches between the two strings.
- Finally, the score is calculated by comparing
-
Example Usage:
- The code demonstrates the
best_shuffle
method on several different input strings and prints the original string, the shuffled string, and the calculated score.
- The code demonstrates the
In summary, the best_shuffle
method aims to find a shuffled string that preserves the original character frequencies while also maximizing the number of characters that remain in the same position as in the original string. It does this by carefully filling the positions in the shuffled string based on the occurrence counts of each letter in the input string.
Source code in the ruby programming language
def best_shuffle(s)
# Fill _pos_ with positions in the order
# that we want to fill them.
pos = []
# g["a"] = [2, 4] implies that s[2] == s[4] == "a"
g = s.length.times.group_by { |i| s[i] }
# k sorts letters from low to high count
k = g.sort_by { |k, v| v.length }.map { |k, v| k }
until g.empty?
k.each do |letter|
g[letter] or next
pos.push(g[letter].pop)
g[letter].empty? and g.delete letter
end
end
# Now fill in _new_ with _letters_ according to each position
# in _pos_, but skip ahead in _letters_ if we can avoid
# matching characters that way.
letters = s.dup
new = "?" * s.length
until letters.empty?
i, p = 0, pos.pop
i += 1 while letters[i] == s[p] and i < (letters.length - 1)
new[p] = letters.slice! i
end
score = new.chars.zip(s.chars).count { |c, d| c == d }
[new, score]
end
%w(abracadabra seesaw elk grrrrrr up a).each do |word|
puts "%s, %s, (%d)" % [word, *best_shuffle(word)]
end
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