How to resolve the algorithm Best shuffle step by step in the Wren programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Best shuffle step by step in the Wren programming language

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Problem Statement

Shuffle the characters of a string in such a way that as many of the character values are in a different position as possible. A shuffle that produces a randomized result among the best choices is to be preferred. A deterministic approach that produces the same sequence every time is acceptable as an alternative. Display the result as follows: The score gives the number of positions whose character value did not change.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Best shuffle step by step in the Wren programming language

Source code in the wren programming language

import "random" for Random

class BestShuffle {
    static shuffle_(ca) {
        var rand = Random.new()
        var i = ca.count - 1
        while (i >= 1) {
            var r = rand.int(i + 1)
            var tmp = ca[i]
            ca[i] = ca[r]
            ca[r] = tmp
            i = i - 1
        }
    }

    static count_(ca, s1) {
        var count = 0
        for (i in 0...ca.count) if (s1[i] == ca[i]) count = count + 1
        return count
    }

    static invoke(s1) {
        var s2 = s1.toList
        shuffle_(s2)
        for (i in 0...s2.count) {
            if (s2[i] == s1[i]) {
                for (j in 0...s2.count) {
                    if (s2[i] != s2[j] && s2[i] != s1[j] && s2[j] != s1[i]) {
                        var tmp = s2[i]
                        s2[i] = s2[j]
                        s2[j] = tmp
                        break
                    }
                }
            }
        }
        return s1 + ", " + s2.join() + ", (" + "%(count_(s2, s1))" + ")"
    }
}

var words = ["tree", "abracadabra", "seesaw", "elk", "grrrrrr", "up", "a"]
words.each { |w| System.print(BestShuffle.invoke(w)) }


  

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