How to resolve the algorithm Best shuffle step by step in the Wren programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Best shuffle step by step in the Wren programming language
Table of Contents
Problem Statement
Shuffle the characters of a string in such a way that as many of the character values are in a different position as possible. A shuffle that produces a randomized result among the best choices is to be preferred. A deterministic approach that produces the same sequence every time is acceptable as an alternative. Display the result as follows: The score gives the number of positions whose character value did not change.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Best shuffle step by step in the Wren programming language
Source code in the wren programming language
import "random" for Random
class BestShuffle {
static shuffle_(ca) {
var rand = Random.new()
var i = ca.count - 1
while (i >= 1) {
var r = rand.int(i + 1)
var tmp = ca[i]
ca[i] = ca[r]
ca[r] = tmp
i = i - 1
}
}
static count_(ca, s1) {
var count = 0
for (i in 0...ca.count) if (s1[i] == ca[i]) count = count + 1
return count
}
static invoke(s1) {
var s2 = s1.toList
shuffle_(s2)
for (i in 0...s2.count) {
if (s2[i] == s1[i]) {
for (j in 0...s2.count) {
if (s2[i] != s2[j] && s2[i] != s1[j] && s2[j] != s1[i]) {
var tmp = s2[i]
s2[i] = s2[j]
s2[j] = tmp
break
}
}
}
}
return s1 + ", " + s2.join() + ", (" + "%(count_(s2, s1))" + ")"
}
}
var words = ["tree", "abracadabra", "seesaw", "elk", "grrrrrr", "up", "a"]
words.each { |w| System.print(BestShuffle.invoke(w)) }
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