How to resolve the algorithm Binary strings step by step in the Lua programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Binary strings step by step in the Lua programming language

Table of Contents

Problem Statement

Many languages have powerful and useful (binary safe) string manipulation functions, while others don't, making it harder for these languages to accomplish some tasks. This task is about creating functions to handle binary strings (strings made of arbitrary bytes, i.e. byte strings according to Wikipedia) for those languages that don't have built-in support for them. If your language of choice does have this built-in support, show a possible alternative implementation for the functions or abilities already provided by the language. In particular the functions you need to create are:

Possible contexts of use: compression algorithms (like LZW compression), L-systems (manipulation of symbols), many more.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Binary strings step by step in the Lua programming language

Source code in the lua programming language

foo = 'foo'             -- Ducktyping foo to be string 'foo'
bar = 'bar'
assert (foo == "foo")   -- Comparing string var to string literal
assert (foo ~= bar)
str = foo               -- Copy foo contents to str
if #str == 0 then       -- # operator returns string length
    print 'str is empty'
end
str=str..string.char(50)-- Char concatenated with .. operator
substr = str:sub(1,3)   -- Extract substring from index 1 to 3, inclusively

str = "string string string string"
-- This function will replace all occurances of 'replaced' in a string with 'replacement'
function replaceAll(str,replaced,replacement)
    local function sub (a,b)
        if b > a then
            return str:sub(a,b)
        end
        return nil
    end
    a,b = str:find(replaced)
    while a do
        str = str:sub(1,a-1) .. replacement .. str:sub(b+1,#str)
        a,b = str:find(replaced)
    end
    return str
end
str = replaceAll (str, 'ing', 'ong')
print (str)

str = foo .. bar -- Strings concatenate with .. operator


  

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