How to resolve the algorithm Brazilian numbers step by step in the BASIC programming language
How to resolve the algorithm Brazilian numbers step by step in the BASIC programming language
Table of Contents
Problem Statement
Brazilian numbers are so called as they were first formally presented at the 1994 math Olympiad Olimpiada Iberoamericana de Matematica in Fortaleza, Brazil. Brazilian numbers are defined as: The set of positive integer numbers where each number N has at least one natural number B where 1 < B < N-1 where the representation of N in base B has all equal digits.
All even integers 2P >= 8 are Brazilian because 2P = 2(P-1) + 2, which is 22 in base P-1 when P-1 > 2. That becomes true when P >= 4.
More common: for all all integers R and S, where R > 1 and also S-1 > R, then RS is Brazilian because RS = R(S-1) + R, which is RR in base S-1
The only problematic numbers are squares of primes, where R = S. Only 11^2 is brazilian to base 3.
All prime integers, that are brazilian, can only have the digit 1. Otherwise one could factor out the digit, therefore it cannot be a prime number. Mostly in form of 111 to base Integer(sqrt(prime number)). Must be an odd count of 1 to stay odd like primes > 2
Write a routine (function, whatever) to determine if a number is Brazilian and use the routine to show here, on this page;
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Brazilian numbers step by step in the BASIC programming language
Source code in the basic programming language
1000 REM Brazilian numbers
1010 DECLARE EXTERNAL FUNCTION IsBrazilian
1020 DECLARE EXTERNAL FUNCTION SameDigits
1030 DECLARE EXTERNAL FUNCTION IsPrime
1040 PRINT "First 20 Brazilian numbers:"
1050 LET C = 0
1060 LET N = 7
1070 DO WHILE C < 20
1080 IF IsBrazilian(N) <> 0 THEN
1090 PRINT N;
1100 LET C = C + 1
1110 END IF
1120 LET N = N + 1
1130 LOOP
1140 PRINT
1150 PRINT
1160 PRINT "First 20 odd Brazilian numbers:"
1170 LET C = 0
1180 LET N = 7
1190 DO WHILE C < 20
1200 IF IsBrazilian(N) <> 0 THEN
1210 PRINT N;
1220 LET C = C + 1
1230 END IF
1240 LET N = N + 2
1250 LOOP
1260 PRINT
1270 PRINT
1280 PRINT "First 20 prime Brazilian numbers:"
1290 LET C = 0
1300 LET N = 7
1310 DO WHILE C < 20
1320 IF IsBrazilian(N) <> 0 THEN
1330 PRINT N;
1340 LET C = C + 1
1350 END IF
1360 DO
1370 LET N = N + 2
1380 LOOP WHILE IsPrime(N) = 0
1390 LOOP
1400 PRINT
1410 END
1420 REM
1430 EXTERNAL FUNCTION IsBrazilian(N)
1440 REM Result: 1 if N is Brazilian, 0 otherwise
1450 IF N < 7 THEN
1460 LET IsBrazilian = 0
1470 ELSEIF (MOD(N, 2) = 0) AND (N >= 8) THEN
1480 LET IsBrazilian = 1
1490 ELSE
1500 FOR B = 2 TO N - 2
1510 IF SameDigits(N, B) <> 0 THEN
1520 LET IsBrazilian = 1
1530 EXIT FUNCTION
1540 END IF
1550 NEXT B
1560 LET IsBrazilian = 0
1570 END IF
1580 END FUNCTION
1590 REM
1600 EXTERNAL FUNCTION SameDigits(N, B)
1610 REM Result: 1 if N has same digits in the base B, 0 otherwise
1620 LET NL = N ! Local N
1630 LET F = MOD(NL, B)
1640 LET NL = INT(NL / B)
1650 DO WHILE NL > 0
1660 IF MOD(NL, B) <> F THEN
1670 LET SameDigits = 0
1680 EXIT FUNCTION
1690 END IF
1700 LET NL = INT(NL / B)
1710 LOOP
1720 LET SameDigits = 1
1730 END FUNCTION
1740 REM
1750 EXTERNAL FUNCTION IsPrime(N)
1760 REM Result: non-zero if N is prime, 0 otherwise
1770 IF N < 2 THEN
1780 LET IsPrime = 0
1790 ELSEIF MOD(N, 2) = 0 THEN
1800 REM IsPrime = (N = 2)
1810 IF N = 2 THEN
1820 LET IsPrime = 1
1830 ELSE
1840 LET IsPrime = 0
1850 END IF
1860 ELSEIF MOD(N, 3) = 0 THEN
1870 REM IsPrime = (N = 3)
1880 IF N = 3 THEN
1890 LET IsPrime = 1
1900 ELSE
1910 LET IsPrime = 0
1920 END IF
1930 ELSE
1940 LET D = 5
1950 DO WHILE D * D <= N
1960 IF MOD(N, D) = 0 THEN
1970 LET IsPrime = 0
1980 EXIT FUNCTION
1990 ELSE
2000 LET D = D + 2
2010 IF MOD(N, D) = 0 THEN
2020 LET IsPrime = 0
2030 EXIT FUNCTION
2040 ELSE
2050 LET D = D + 4
2060 END IF
2070 END IF
2080 LOOP
2090 LET IsPrime = 1
2100 END IF
2110 END FUNCTION
Function sameDigits(Byval n As Integer, Byval b As Integer) As Boolean
Dim f As Integer = n Mod b : n \= b
While n > 0
If n Mod b <> f Then Return False Else n \= b
Wend
Return True
End Function
Function isBrazilian(Byval n As Integer) As Boolean
If n < 7 Then Return False
If n Mod 2 = 0 Then Return True
For b As Integer = 2 To n - 2
If sameDigits(n, b) Then Return True
Next b
Return False
End Function
Function isPrime(Byval n As Integer) As Boolean
If n < 2 Then Return False
If n Mod 2 = 0 Then Return n = 2
If n Mod 3 = 0 Then Return n = 3
Dim d As Integer = 5
While d * d <= n
If n Mod d = 0 Then Return False Else d += 2
If n Mod d = 0 Then Return False Else d += 4
Wend
Return True
End Function
Dim kind(2) As String ={"", "odd", "prime"}
For i As Integer = 0 To 2
Print Using "First 20 & Brazilian numbers: "; kind(i)
Dim Limit As Integer = 20, n As Integer = 7
Do
If isBrazilian(n) Then Print Using "& "; n; : Limit -= 1
Select Case kind(i)
Case "" : n += 1
Case "odd" : n += 2
Case "prime" : Do : n += 2 : Loop Until isPrime(n)
End Select
Loop While Limit > 0
Next i
Sleep
10 REM Brazilian numbers
20 PRINT "First 20 Brazilian numbers:"
30 C=0:N=7
40 IF C>=20 THEN 90
50 GOSUB 320
60 IF BR THEN PRINT N;:C=C+1
70 N=N+1
80 GOTO 40
90 PRINT:PRINT
100 PRINT "First 20 odd Brazilian numbers:"
110 C=0:N=7
120 IF C>=20 THEN 170
130 GOSUB 320
140 IF BR THEN PRINT N;:C=C+1
150 N=N+2
160 GOTO 120
170 PRINT:PRINT
180 PRINT "First 12 prime Brazilian numbers:"
190 C=0:N=7
200 IF C>=12 THEN 270
210 GOSUB 320
220 IF BR THEN PRINT N;:C=C+1
230 N=N+2
240 GOSUB 530
250 IF NOT PRM THEN 230
260 GOTO 200
270 PRINT
280 END
290 REM ** Is Brazilian?
300 REM Result: BR=-1 if N is Brazilian
310 REM 0 otherwise
320 IF N<7 THEN BR=0:RETURN
330 IF INT(N/2)*2=N AND N>=8 THEN BR=-1:RETURN
340 FOR B=2 TO N-2
350 GOSUB 430
360 IF SMD THEN BR=-1:RETURN
370 NEXT B
380 BR=0
390 RETURN
400 REM ** Same digits?
410 REM Result: SMD=-1 if N has same digits in B,
420 REM 0 otherwise
430 NL=N:REM "Local" N
440 NDB=INT(NL/B)
450 F=NL-NDB*B
460 NL=NDB:NDB=INT(NL/B)
470 IF NL<=0 THEN SMD=-1:RETURN
480 IF NL-NDB*B<>F THEN SMD=0:RETURN
490 NL=INT(NL/B):NDB=INT(NL/B)
500 GOTO 470
510 REM ** Is prime?
520 REM Result: PRM=-1 if N prime, 0 otherwise
530 IF N<2 THEN PRM=0:RETURN
540 IF INT(N/2)*2=N THEN PRM=N=2:RETURN
550 IF INT(N/3)*3=N THEN PRM=N=3:RETURN
560 D=5
570 IF D*D>N THEN PRM=-1:RETURN
580 IF INT(N/D)*D=N THEN PRM=0:RETURN
590 D=D+2
600 IF INT(N/D)*D=N THEN PRM=0:RETURN
610 D=D+4
620 GOTO 570
Module Module1
Function sameDigits(ByVal n As Integer, ByVal b As Integer) As Boolean
Dim f As Integer = n Mod b : n \= b : While n > 0
If n Mod b <> f Then Return False Else n \= b
End While : Return True
End Function
Function isBrazilian(ByVal n As Integer) As Boolean
If n < 7 Then Return False
If n Mod 2 = 0 Then Return True
For b As Integer = 2 To n - 2
If sameDigits(n, b) Then Return True
Next : Return False
End Function
Function isPrime(ByVal n As Integer) As Boolean
If n < 2 Then Return False
If n Mod 2 = 0 Then Return n = 2
If n Mod 3 = 0 Then Return n = 3
Dim d As Integer = 5
While d * d <= n
If n Mod d = 0 Then Return False Else d += 2
If n Mod d = 0 Then Return False Else d += 4
End While : Return True
End Function
Sub Main(args As String())
For Each kind As String In {" ", " odd ", " prime "}
Console.WriteLine("First 20{0}Brazilian numbers:", kind)
Dim Limit As Integer = 20, n As Integer = 7
Do
If isBrazilian(n) Then Console.Write("{0} ", n) : Limit -= 1
Select Case kind
Case " " : n += 1
Case " odd " : n += 2
Case " prime " : Do : n += 2 : Loop Until isPrime(n)
End Select
Loop While Limit > 0
Console.Write(vbLf & vbLf)
Next
End Sub
End Module
Imports System
Module Module1
' flags:
Const _
PrMk As Integer = 0, ' a number that is prime
SqMk As Integer = 1, ' a number that is the square of a prime number
UpMk As Integer = 2, ' a number that can be factored (aka un-prime)
BrMk As Integer = -2, ' a prime number that is also a Brazilian number
Excp As Integer = 121 ' exception square - the only square prime that is a Brazilian
Dim pow As Integer = 9,
max As Integer ' maximum sieve array length
' An upper limit of the required array length can be calculated Like this:
' power of 10 fraction limit actual result
' 1 2 / 1 * 10 = 20 20
' 2 4 / 3 * 100 = 133 132
' 3 6 / 5 * 1000 = 1200 1191
' 4 8 / 7 * 10000 = 11428 11364
' 5 10/ 9 * 100000 = 111111 110468
' 6 12/11 * 1000000 = 1090909 1084566
' 7 14/13 * 10000000 = 10769230 10708453
' 8 16/15 * 100000000 = 106666666 106091516
' 9 18/17 * 1000000000 = 1058823529 1053421821
' powers above 9 are impractical because of the maximum array length in VB.NET,
' which is around the UInt32.MaxValue, Or 4294967295
Dim PS As SByte() ' the prime/Brazilian number sieve
' once the sieve is populated, primes are <= 0, non-primes are > 0,
' Brazilian numbers are (< 0) or (> 1)
' 121 is a special case, in the sieve it is marked with the BrMk (-2)
' typical sieve of Eratosthenes algorithm
Sub PrimeSieve(ByVal top As Integer)
PS = New SByte(top) {} : Dim i, ii, j As Integer
i = 2 : j = 4 : PS(j) = SqMk : While j < top - 2 : j += 2 : PS(j) = UpMk : End While
i = 3 : j = 9 : PS(j) = SqMk : While j < top - 6 : j += 6 : PS(j) = UpMk : End While
i = 5 : ii = 25 : While ii < top
If PS(i) = PrMk Then
j = (top - i) / i : If (j And 1) = 0 Then j -= 1
Do : If PS(j) = PrMk Then PS(i * j) = UpMk
j -= 2 : Loop While j > i : PS(ii) = SqMk
End If
Do : i += 2 : Loop While PS(i) <> PrMk : ii = i * i
End While
End Sub
' consults the sieve and returns whether a number is Brazilian
Function IsBr(ByVal number As Integer) As Boolean
Return Math.Abs(PS(number)) > SqMk
End Function
' shows the first few Brazilian numbers of several kinds
Sub FirstFew(ByVal kind As String, ByVal amt As Integer)
Console.WriteLine(vbLf & "The first {0} {1}Brazilian Numbers are:", amt, kind)
Dim i As Integer = 7 : While amt > 0
If IsBr(i) Then amt -= 1 : Console.Write("{0} ", i)
Select Case kind : Case "odd " : i += 2
Case "prime " : Do : i += 2 : Loop While PS(i) <> BrMk OrElse i = Excp
Case Else : i += 1 : End Select : End While : Console.WriteLine()
End Sub
' expands a 111_X number into an integer
Function Expand(ByVal NumberOfOnes As Integer, ByVal Base As Integer) As Integer
Dim res As Integer = 1
While NumberOfOnes > 1 AndAlso res < Integer.MaxValue \ Base
res = res * Base + 1 : NumberOfOnes -= 1 : End While
If res > max OrElse res < 0 Then res = 0
Return res
End Function
' returns an elapsed time string
Function TS(ByVal fmt As String, ByRef st As DateTime, ByVal Optional reset As Boolean = False) As String
Dim n As DateTime = DateTime.Now,
res As String = String.Format(fmt, (n - st).TotalMilliseconds)
If reset Then st = n
Return res
End Function
Sub Main(args As String())
Dim p2 As Integer = pow << 1, primes(6) As Integer, n As Integer,
st As DateTime = DateTime.Now, st0 As DateTime = st,
p10 As Integer = CInt(Math.Pow(10, pow)), p As Integer = 10, cnt As Integer = 0
max = CInt(((CLng((p10)) * p2) / (p2 - 1))) : PrimeSieve(max)
Console.WriteLine(TS("Sieving took {0} ms", st, True))
' make short list of primes before Brazilians are added
n = 3 : For i As Integer = 0 To primes.Length - 1
primes(i) = n : Do : n += 2 : Loop While PS(n) <> 0 : Next
Console.WriteLine(vbLf & "Checking first few prime numbers of sequential ones:" &
vbLf & "ones checked found")
' now check the '111_X' style numbers. many are factorable, but some are prime,
' then re-mark the primes found in the sieve as Brazilian.
' curiously, only the numbers with a prime number of ones will turn out, so
' restricting the search to those saves time. no need to wast time on even numbers of ones,
' or 9 ones, 15 ones, etc...
For Each i As Integer In primes
Console.Write("{0,4}", i) : cnt = 0 : n = 2 : Do
If (n - 1) Mod i <> 0 Then
Dim br As Long = Expand(i, n)
If br > 0 Then
If PS(br) < UpMk Then PS(br) = BrMk : cnt += 1
Else
Console.WriteLine("{0,8}{1,6}", n, cnt) : Exit Do
End If
End If : n += 1 : Loop While True
Next
Console.WriteLine(TS("Adding Brazilian primes to the sieve took {0} ms", st, True))
For Each s As String In ",odd ,prime ".Split(",") : FirstFew(s, 20) : Next
Console.WriteLine(TS(vbLf & "Required output took {0} ms", st, True))
Console.WriteLine(vbLf & "Decade count of Brazilian numbers:")
n = 6 : cnt = 0 : Do : While cnt < p : n += 1 : If IsBr(n) Then cnt += 1
End While
Console.WriteLine("{0,15:n0}th is {1,-15:n0} {2}", cnt, n, TS("time: {0} ms", st))
If p < p10 Then p *= 10 Else Exit Do
Loop While (True) : PS = New SByte(-1) {}
Console.WriteLine(vbLf & "Total elapsed was {0} ms", (DateTime.Now - st0).TotalMilliseconds)
If System.Diagnostics.Debugger.IsAttached Then Console.ReadKey()
End Sub
End Module
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