How to resolve the algorithm Caesar cipher step by step in the OCaml programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Caesar cipher step by step in the OCaml programming language
Table of Contents
Problem Statement
Implement a Caesar cipher, both encoding and decoding. The key is an integer from 1 to 25. This cipher rotates (either towards left or right) the letters of the alphabet (A to Z). The encoding replaces each letter with the 1st to 25th next letter in the alphabet (wrapping Z to A). So key 2 encrypts "HI" to "JK", but key 20 encrypts "HI" to "BC". This simple "mono-alphabetic substitution cipher" provides almost no security, because an attacker who has the encoded message can either use frequency analysis to guess the key, or just try all 25 keys. Caesar cipher is identical to Vigenère cipher with a key of length 1. Also, Rot-13 is identical to Caesar cipher with key 13.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Caesar cipher step by step in the OCaml programming language
Source code in the ocaml programming language
let islower c =
c >= 'a' && c <= 'z'
let isupper c =
c >= 'A' && c <= 'Z'
let rot x str =
let upchars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
and lowchars = "abcdefghijklmnopqrstuvwxyz" in
let rec decal x =
if x < 0 then decal (x + 26) else x
in
let x = (decal x) mod 26 in
let decal_up = x - (int_of_char 'A')
and decal_low = x - (int_of_char 'a') in
String.map (fun c ->
if islower c then
let j = ((int_of_char c) + decal_low) mod 26 in
lowchars.[j]
else if isupper c then
let j = ((int_of_char c) + decal_up) mod 26 in
upchars.[j]
else
c
) str
let () =
let key = 3 in
let orig = "The five boxing wizards jump quickly" in
let enciphered = rot key orig in
print_endline enciphered;
let deciphered = rot (- key) enciphered in
print_endline deciphered;
Printf.printf "equal: %b\n" (orig = deciphered)
;;
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