How to resolve the algorithm Cistercian numerals step by step in the Nim programming language
How to resolve the algorithm Cistercian numerals step by step in the Nim programming language
Table of Contents
Problem Statement
Cistercian numerals were used across Europe by Cistercian monks during the Late Medieval Period as an alternative to Roman numerals. They were used to represent base 10 integers from 0 to 9999. All Cistercian numerals begin with a vertical line segment, which by itself represents the number 0. Then, glyphs representing the digits 1 through 9 are optionally added to the four quadrants surrounding the vertical line segment. These glyphs are drawn with vertical and horizontal symmetry about the initial line segment. Each quadrant corresponds to a digit place in the number: Please consult the following image for examples of Cistercian numerals showing each glyph: [1] Due to the inability to upload images to Rosetta Code as of this task's creation, showing output here on this page is not required. However, it is welcomed — especially for text output.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Cistercian numerals step by step in the Nim programming language
Source code in the nim programming language
const Size = 15
type Canvas = array[Size, array[Size, char]]
func horizontal(canvas: var Canvas; col1, col2, row: Natural) =
for col in col1..col2:
canvas[row][col] = 'x'
func vertical(canvas: var Canvas; row1, row2, col: Natural) =
for row in row1..row2:
canvas[row][col] = 'x'
func diagd(canvas: var Canvas; col1, col2, row: Natural) =
for col in col1..col2:
canvas[row + col - col1][col] = 'x'
func diagu(canvas: var Canvas; col1, col2, row: Natural) =
for col in col1..col2:
canvas[row - col + col1][col] = 'x'
func drawPart(canvas: var Canvas; value: Natural) =
case value
of 1:
canvas.horizontal(6, 10, 0)
of 2:
canvas.horizontal(6, 10, 4)
of 3:
canvas.diagd(6, 10, 0)
of 4:
canvas.diagu(6, 10, 4)
of 5:
canvas.drawPart(1)
canvas.drawPart(4)
of 6:
canvas.vertical(0, 4, 10)
of 7:
canvas.drawPart(1)
canvas.drawPart(6)
of 8:
canvas.drawPart(2)
canvas.drawPart(6)
of 9:
canvas.drawPart(1)
canvas.drawPart(8)
of 10:
canvas.horizontal(0, 4, 0)
of 20:
canvas.horizontal(0, 4, 4)
of 30:
canvas.diagu(0, 4, 4)
of 40:
canvas.diagd(0, 4, 0)
of 50:
canvas.drawPart(10)
canvas.drawPart(40)
of 60:
canvas.vertical(0, 4, 0)
of 70:
canvas.drawPart(10)
canvas.drawPart(60)
of 80:
canvas.drawPart(20)
canvas.drawPart(60)
of 90:
canvas.drawPart(10)
canvas.drawPart(80)
of 100:
canvas.horizontal(6, 10, 14)
of 200:
canvas.horizontal(6, 10, 10)
of 300:
canvas.diagu(6, 10, 14)
of 400:
canvas.diagd(6, 10, 10)
of 500:
canvas.drawPart(100)
canvas.drawPart(400)
of 600:
canvas.vertical(10, 14, 10)
of 700:
canvas.drawPart(100)
canvas.drawPart(600)
of 800:
canvas.drawPart(200)
canvas.drawPart(600)
of 900:
canvas.drawPart(100)
canvas.drawPart(800)
of 1000:
canvas.horizontal(0, 4, 14)
of 2000:
canvas.horizontal(0, 4, 10)
of 3000:
canvas.diagd(0, 4, 10)
of 4000:
canvas.diagu(0, 4, 14)
of 5000:
canvas.drawPart(1000)
canvas.drawPart(4000)
of 6000:
canvas.vertical(10, 14, 0)
of 7000:
canvas.drawPart(1000)
canvas.drawPart(6000)
of 8000:
canvas.drawPart(2000)
canvas.drawPart(6000)
of 9000:
canvas.drawPart(1000)
canvas.drawPart(8000)
else:
raise newException(ValueError, "wrong value for 'drawPart'")
func draw(canvas: var Canvas; value: Natural) =
var val = value
let thousands = val div 1000
val = val mod 1000
let hundreds = val div 100
val = val mod 100
let tens = val div 10
let ones = val mod 10
if thousands != 0:
canvas.drawPart(1000 * thousands)
if hundreds != 0:
canvas.drawPart(100 * hundreds)
if tens != 0:
canvas.drawPart(10 * tens)
if ones != 0:
canvas.drawPart(ones)
func cistercian(n: Natural): Canvas =
for row in result.mitems:
for cell in row.mitems: cell = ' '
row[5] = 'x'
result.draw(n)
proc `$`(canvas: Canvas): string =
for row in canvas:
for cell in row:
result.add cell
result.add '\n'
when isMainModule:
for number in [0, 1, 20, 300, 4000, 5555, 6789, 9999]:
echo number, ':'
echo cistercian(number)
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