How to resolve the algorithm Closures/Value capture step by step in the Scala programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Closures/Value capture step by step in the Scala programming language

Table of Contents

Problem Statement

Create a list of ten functions, in the simplest manner possible   (anonymous functions are encouraged),   such that the function at index   i   (you may choose to start   i   from either   0   or   1),   when run, should return the square of the index,   that is,   i 2. Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.

Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over. In imperative languages, one would generally use a loop with a mutable counter variable. For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run. See also: Multiple distinct objects

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Closures/Value capture step by step in the Scala programming language

Source code in the scala programming language

val closures=for(i <- 0 to 9) yield (()=>i*i)
0 to 8 foreach (i=> println(closures(i)()))
println("---\n"+closures(7)())

  

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