How to resolve the algorithm Combinations with repetitions step by step in the Racket programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Combinations with repetitions step by step in the Racket programming language
Table of Contents
Problem Statement
The set of combinations with repetitions is computed from a set,
S
{\displaystyle S}
(of cardinality
n
{\displaystyle n}
), and a size of resulting selection,
k
{\displaystyle k}
, by reporting the sets of cardinality
k
{\displaystyle k}
where each member of those sets is chosen from
S
{\displaystyle S}
. In the real world, it is about choosing sets where there is a “large” supply of each type of element and where the order of choice does not matter. For example: Note that both the order of items within a pair, and the order of the pairs given in the answer is not significant; the pairs represent multisets. Also note that doughnut can also be spelled donut.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Combinations with repetitions step by step in the Racket programming language
Source code in the racket programming language
#lang racket
(define (combinations xs k)
(cond [(= k 0) '(())]
[(empty? xs) '()]
[(append (combinations (rest xs) k)
(map (λ(x) (cons (first xs) x))
(combinations xs (- k 1))))]))
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