Step by Step solution about How to resolve the algorithm Comma quibbling step by step in the Go programming language

The Go program demonstrates how to construct a formatted string based on the number of elements in a given slice of strings.

Key Implementation Details:

1. q Function:
   • This function takes a slice of strings ([]string) as input and returns a formatted string representing the contents of the slice.
   • It handles different cases based on the number of elements in the slice:
     • If the slice is empty, it returns "{}".
     • If the slice has one element, it returns "{" followed by the element and "}".
     • If the slice has two elements, it returns "{" followed by the first element, " and ", then the second element, and "}".
     • For slices with more than two elements, it constructs a string using the elements separated by commas, inserts " and " before the last element, and encloses the string in braces ("{}").

Main Workflow:

In the main function:

1. It calls q with an empty slice and prints the result, which is "{}".
2. It calls q with a slice containing one string "ABC" and prints the result, which is "{"ABC"}".
3. It calls q with a slice containing two strings "ABC" and "DEF" and prints the result, which is "{"ABC and DEF"}".
4. It calls q with a slice containing four strings "ABC", "DEF", "G", and "H" and prints the result, which is "{"ABC, DEF, G and H"}".

Output:

{}
{ABC}
{ABC and DEF}
{ABC, DEF, G and H}

package main

import (
    "fmt"
    "strings"
)

func q(s []string) string {
    switch len(s) {
    case 0:
        return "{}"
    case 1:
        return "{" + s[0] + "}"
    case 2:
        return "{" + s[0] + " and " + s[1] + "}"
    default:
        return "{" +
            strings.Join(s[:len(s)-1], ", ") +
            " and " +
            s[len(s)-1] +
            "}"
    }
}

func main() {
    fmt.Println(q([]string{}))
    fmt.Println(q([]string{"ABC"}))
    fmt.Println(q([]string{"ABC", "DEF"}))
    fmt.Println(q([]string{"ABC", "DEF", "G", "H"}))
}