How to resolve the algorithm Comma quibbling step by step in the PL/I programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Comma quibbling step by step in the PL/I programming language
Table of Contents
Problem Statement
Comma quibbling is a task originally set by Eric Lippert in his blog.
Write a function to generate a string output which is the concatenation of input words from a list/sequence where:
Test your function with the following series of inputs showing your output here on this page:
Note: Assume words are non-empty strings of uppercase characters for this task.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Comma quibbling step by step in the PL/I programming language
Source code in the pl/i programming language
*process or(!);
quib: Proc Options(main);
/*********************************************************************
* 06.10.2013 Walter Pachl
*********************************************************************/
put Edit*process or(!);
quib: Proc Options(main);
/*********************************************************************
* 06.10.2013 Walter Pachl
* 07.10.2013 -"- change "Oxford comma" to and
*********************************************************************/
put Edit(quibbling(''))(Skip,a);
put Edit(quibbling('ABC'))(Skip,a);
put Edit(quibbling('ABC DEF'))(Skip,a);
put Edit(quibbling('ABC DEF G H'))(Skip,a);
return;
quibbling: proc(s) Returns(Char(100) Var);
Dcl s Char(*);
Dcl result Char(100) Var Init('');
Dcl word(10) Char(100) Var;
Dcl (wi,p) Bin Fixed(31);
If s='' Then result='';
Else Do;
Do wi=1 By 1 While(s^='');
p=index(s,' ');
if p=0 Then Do;
word(wi)=s;
s='';
End;
Else Do;
word(wi)=left(s,p-1);
s=substr(s,p+1);
End;
end;
wn=wi-1;
result=word(1);
Do i=2 To wn-1;
result=result!!', '!!word(i);
End;
If wn>1 Then
result=result!!' and '!!word(wn);
End;
Return('{'!!result!!'}');
End;
End;
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