Step by Step solution about How to resolve the algorithm Comma quibbling step by step in the Python programming language

The provided source code defines three Python functions, strcat, commaQuibble, and quibble, that format a list of strings into a string with a specific grammatical structure: strcat: This function takes a sequence, typically a list of strings, as an argument and converts it into a string enclosed in curly braces with a comma-separated list of the elements. If there are multiple elements in the sequence, it replaces the last comma with the word "and" to create a grammatically correct sentence. For example:

Input: ["ABC", "DEF"]
Output: "{ABC and DEF}"

commaQuibble: This function is similar to strcat but uses the phrase "and" instead of a comma to separate the last two elements. For example:

Input: ["ABC", "DEF"]
Output: "{ABC and DEF}"

quibble: This function creates a string with the same structure as strcat, but it uses a more complex logic to add the "and" phrase. It handles edge cases like an empty list or a list with only one element. For example:

Input: ["ABC", "DEF"]
Output: "{ABC and DEF}"

These functions demonstrate various ways to format a list of strings into a string with a specific grammatical structure, such as enclosing it in curly braces and using "and" or commas to separate the elements.

>>> def strcat(sequence):
    return '{%s}' % ', '.join(sequence)[::-1].replace(',', 'dna ', 1)[::-1]

>>> for seq in ([], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]):
    print('Input: %-24r -> Output: %r' % (seq, strcat(seq)))

	
Input: []                       -> Output: '{}'
Input: ['ABC']                  -> Output: '{ABC}'
Input: ['ABC', 'DEF']           -> Output: '{ABC and DEF}'
Input: ['ABC', 'DEF', 'G', 'H'] -> Output: '{ABC, DEF, G and H}'
>>>


def commaQuibble(s):
    return '{%s}' % ' and '.join(s).replace(' and ', ', ', len(s) - 2)

for seq in ([], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]):
	print('Input: %-24r -> Output: %r' % (seq, commaQuibble(seq)))


>>> def quibble(s):
    return ('{' +
                (', '.join(s[:-1]) + ' and ' if len(s) > 1 else '') +
	        (s[-1] if s else '') +
	    '}')

>>> for seq in ([], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]):
	print('Input: %-24r -> Output: %r' % (seq, quibble(seq)))

	
Input: []                       -> Output: '{}'
Input: ['ABC']                  -> Output: '{ABC}'
Input: ['ABC', 'DEF']           -> Output: '{ABC and DEF}'
Input: ['ABC', 'DEF', 'G', 'H'] -> Output: '{ABC, DEF, G and H}'
>>>