How to resolve the algorithm Compare a list of strings step by step in the ALGOL W programming language
How to resolve the algorithm Compare a list of strings step by step in the ALGOL W programming language
Table of Contents
Problem Statement
Given a list of arbitrarily many strings, show how to:
Each of those two tests should result in a single true or false value, which could be used as the condition of an if statement or similar. If the input list has less than two elements, the tests should always return true. There is no need to provide a complete program and output. Assume that the strings are already stored in an array/list/sequence/tuple variable (whatever is most idiomatic) with the name strings, and just show the expressions for performing those two tests on it (plus of course any includes and custom functions etc. that it needs), with as little distractions as possible. Try to write your solution in a way that does not modify the original list, but if it does then please add a note to make that clear to readers. If you need further guidance/clarification, see #Perl and #Python for solutions that use implicit short-circuiting loops, and #Raku for a solution that gets away with simply using a built-in language feature.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Compare a list of strings step by step in the ALGOL W programming language
Source code in the algol programming language
% returns true if all elements of the string array a are equal, false otherwise %
% As Algol W procedures cannot determine the bounds of an array, the bounds %
% must be specified in lo and hi %
logical procedure allStringsEqual ( string(256) array a ( * )
; integer value lo, hi
) ;
begin
logical same;
integer listPos;
same := true;
listPos := lo + 1;
while same and listPos <= hi do begin
same := a( lo ) = a( listPos );
listPos := listPos + 1
end;
same
end allStringsEqual ;
% returns true if the elements of the string array a are in ascending order, %
% false otherwise %
% As Algol W procedures cannot determine the bounds of an array, the bounds %
% must be specified in lo and hi %
logical procedure ascendingOrder ( string(256) array a ( * )
; integer value lo, hi
) ;
begin
logical ordered;
integer listPos;
ordered := true;
listPos := lo + 1;
while ordered and listPos <= hi do begin
ordered := a( listPos - 1 ) < a( listPos );
listPos := listPos + 1
end;
ordered
end ascendingOrder ;
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