How to resolve the algorithm Compare a list of strings step by step in the Nanoquery programming language
How to resolve the algorithm Compare a list of strings step by step in the Nanoquery programming language
Table of Contents
Problem Statement
Given a list of arbitrarily many strings, show how to:
Each of those two tests should result in a single true or false value, which could be used as the condition of an if statement or similar. If the input list has less than two elements, the tests should always return true. There is no need to provide a complete program and output. Assume that the strings are already stored in an array/list/sequence/tuple variable (whatever is most idiomatic) with the name strings, and just show the expressions for performing those two tests on it (plus of course any includes and custom functions etc. that it needs), with as little distractions as possible. Try to write your solution in a way that does not modify the original list, but if it does then please add a note to make that clear to readers. If you need further guidance/clarification, see #Perl and #Python for solutions that use implicit short-circuiting loops, and #Raku for a solution that gets away with simply using a built-in language feature.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Compare a list of strings step by step in the Nanoquery programming language
Source code in the nanoquery programming language
// a function to test if a list of strings are equal
def stringsEqual(stringList)
// if the list is empty, return true
if (len(stringList) = 0)
return true
end
// otherwise get the first value and check for equality
toCompare = stringList[0]
equal = true
for (i = 1) (equal && (i < len(stringList))) (i = i + 1)
equal = (toCompare = stringList[i])
end for
// return whether the strings are equal or not
return equal
end
// a function to test if a list of strings are are less than each other
def stringsLessThan(stringList)
// if the list is empty, return true
if (len(stringList) = 0)
return true
end
// otherwise get the first value and check for less than
toCompare = stringList[0]
lessThan = true
for (i = 1) (lessThan && (i < len(stringList))) (i = i + 1)
lessThan = (toCompare < stringList[i])
toCompare = stringList[i]
end for
// return whether the string were less than each other or not
return lessThan
end
You may also check:How to resolve the algorithm Calculating the value of e step by step in the Maple programming language
You may also check:How to resolve the algorithm Symmetric difference step by step in the K programming language
You may also check:How to resolve the algorithm Sum and product of an array step by step in the Python programming language
You may also check:How to resolve the algorithm Jump anywhere step by step in the Retro programming language
You may also check:How to resolve the algorithm Matrix multiplication step by step in the BASIC programming language