How to resolve the algorithm Continued fraction/Arithmetic/Construct from rational number step by step in the Rust programming language
How to resolve the algorithm Continued fraction/Arithmetic/Construct from rational number step by step in the Rust programming language
Table of Contents
Problem Statement
The purpose of this task is to write a function
r 2 c f
(
i n t
{\displaystyle {\mathit {r2cf}}(\mathrm {int} }
N
1
,
i n t
{\displaystyle N_{1},\mathrm {int} }
N
2
)
{\displaystyle N_{2})}
, or
r 2 c f
(
F r a c t i o n
{\displaystyle {\mathit {r2cf}}(\mathrm {Fraction} }
N )
{\displaystyle N)}
, which will output a continued fraction assuming: The function should output its results one digit at a time each time it is called, in a manner sometimes described as lazy evaluation. To achieve this it must determine: the integer part; and remainder part, of
N
1
{\displaystyle N_{1}}
divided by
N
2
{\displaystyle N_{2}}
. It then sets
N
1
{\displaystyle N_{1}}
to
N
2
{\displaystyle N_{2}}
and
N
2
{\displaystyle N_{2}}
to the determined remainder part. It then outputs the determined integer part. It does this until
a b s
(
N
2
)
{\displaystyle \mathrm {abs} (N_{2})}
is zero. Demonstrate the function by outputing the continued fraction for:
2
{\displaystyle {\sqrt {2}}}
should approach
[ 1 ; 2 , 2 , 2 , 2 , … ]
{\displaystyle [1;2,2,2,2,\ldots ]}
try ever closer rational approximations until boredom gets the better of you: Try : Observe how this rational number behaves differently to
2
{\displaystyle {\sqrt {2}}}
and convince yourself that, in the same way as
3.7
{\displaystyle 3.7}
may be represented as
3.70
{\displaystyle 3.70}
when an extra decimal place is required,
[ 3 ; 7 ]
{\displaystyle [3;7]}
may be represented as
[ 3 ; 7 , ∞ ]
{\displaystyle [3;7,\infty ]}
when an extra term is required.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Continued fraction/Arithmetic/Construct from rational number step by step in the Rust programming language
Source code in the rust programming language
struct R2cf {
n1: i64,
n2: i64
}
// This iterator generates the continued fraction representation from the
// specified rational number.
impl Iterator for R2cf {
type Item = i64;
fn next(&mut self) -> Option<i64> {
if self.n2 == 0 {
None
}
else {
let t1 = self.n1 / self.n2;
let t2 = self.n2;
self.n2 = self.n1 - t1 * t2;
self.n1 = t2;
Some(t1)
}
}
}
fn r2cf(n1: i64, n2: i64) -> R2cf {
R2cf { n1: n1, n2: n2 }
}
macro_rules! printcf {
($x:expr, $y:expr) => (println!("{:?}", r2cf($x, $y).collect::<Vec<_>>()));
}
fn main() {
printcf!(1, 2);
printcf!(3, 1);
printcf!(23, 8);
printcf!(13, 11);
printcf!(22, 7);
printcf!(-152, 77);
printcf!(14_142, 10_000);
printcf!(141_421, 100_000);
printcf!(1_414_214, 1_000_000);
printcf!(14_142_136, 10_000_000);
printcf!(31, 10);
printcf!(314, 100);
printcf!(3142, 1000);
printcf!(31_428, 10_000);
printcf!(314_285, 100_000);
printcf!(3_142_857, 1_000_000);
printcf!(31_428_571, 10_000_000);
printcf!(314_285_714, 100_000_000);
}
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