How to resolve the algorithm Convert seconds to compound duration step by step in the 11l programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Convert seconds to compound duration step by step in the 11l programming language
Table of Contents
Problem Statement
Write a function or program which: This is detailed below (e.g., "2 hr, 59 sec").
Demonstrate that it passes the following three test-cases: Test CasesDetailsThe following five units should be used: However, only include quantities with non-zero values in the output (e.g., return "1 d" and not "0 wk, 1 d, 0 hr, 0 min, 0 sec"). Give larger units precedence over smaller ones as much as possible (e.g., return 2 min, 10 sec and not 1 min, 70 sec or 130 sec) Mimic the formatting shown in the test-cases (quantities sorted from largest unit to smallest and separated by comma+space; value and unit of each quantity separated by space).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Convert seconds to compound duration step by step in the 11l programming language
Source code in the 11l programming language
F duration(=sec)
[Int] t
L(dm) [60, 60, 24, 7]
Int m
(sec, m) = (sec I/ dm, sec % dm)
t.insert(0, m)
t.insert(0, sec)
R zip(t, [‘wk’, ‘d’, ‘hr’, ‘min’, ‘sec’]).filter(num_unit -> num_unit[0] > 0).map(num_unit -> num_unit[0]‘ ’num_unit[1]).join(‘, ’)
print(duration(7259))
print(duration(86400))
print(duration(6000000))
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