How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language

Table of Contents

Problem Statement

Write a function or program which: This is detailed below (e.g., "2 hr, 59 sec").

Demonstrate that it passes the following three test-cases: Test CasesDetailsThe following five units should be used: However, only include quantities with non-zero values in the output (e.g., return "1 d" and not "0 wk, 1 d, 0 hr, 0 min, 0 sec"). Give larger units precedence over smaller ones as much as possible (e.g., return 2 min, 10 sec and not 1 min, 70 sec or 130 sec) Mimic the formatting shown in the test-cases (quantities sorted from largest unit to smallest and separated by comma+space; value and unit of each quantity separated by space).

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language

The Julia source code provided defines a function called duration that takes an integer representing the number of seconds as input and returns a string representing the duration in a human-readable format. Here's how this code works:

  1. Initialization: The function initializes an empty array t of type Array{Int, 1}. This array will be used to store the values for weeks, days, hours, minutes, and seconds.

  2. Loop Through Units: The code then enters a loop that iterates through the following units in descending order: weeks, days, hours, minutes, and seconds. The loop uses the for comprehension to generate a sequence of tuples (divisor, unit) where divisor is the number of seconds in the unit and unit is the corresponding unit abbreviation.

  3. Dividing by Units: Inside the loop, it performs the following operations:

    • Divides the input sec by the current divisor, storing the remainder in m. This effectively computes the number of complete units (e.g., weeks, days, hours) elapsed within the total duration.
    • Updates sec to the remaining seconds after accounting for the current unit.
    • Pushes the computed m value as the first element of the t array.
  4. Push Last Element: After the loop completes, it pushes the final value of sec, representing the remaining seconds, as the first element of t.

  5. Construct Result String: The code then constructs a string by iterating through the t array and zip-combining it with the unit array. For each pair of (num, unit) in the result, it constructs a string in the format "$num$unit" (e.g., "1w", "2d") but only includes the strings where num is greater than 0 (to avoid displaying zero units).

  6. Join and Return: Finally, it joins all the non-zero duration strings together using commas and returns the result string.

Example Usages:

After defining the duration function, the code includes several @show calls to demonstrate its usage:

  • @show duration(7259): This call displays the duration string for 7259 seconds, which is approximately "2h 1m 19s".
  • @show duration(86400): This call shows the duration string for 86400 seconds, which is equivalent to a day and is displayed as "1d".
  • @show duration(6000000): This call showcases the duration string for 6000000 seconds, which is roughly 69 days and is displayed as "1w 5d 5h 46m 40s".

Source code in the julia programming language

# 1.x
function duration(sec::Integer)::String
    t = Array{Int}([])
    for dm in (60, 60, 24, 7)
        sec, m = divrem(sec, dm)
        pushfirst!(t, m)
    end
    pushfirst!(t, sec)
    return join(["$num$unit" for (num, unit) in zip(t, ["w", "d", "h", "m", "s"]) if num > 0], ", ")
end

@show duration(7259)
@show duration(86400)
@show duration(6000000)


  

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