How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language
How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language
Table of Contents
Problem Statement
Write a function or program which: This is detailed below (e.g., "2 hr, 59 sec").
Demonstrate that it passes the following three test-cases: Test CasesDetailsThe following five units should be used: However, only include quantities with non-zero values in the output (e.g., return "1 d" and not "0 wk, 1 d, 0 hr, 0 min, 0 sec"). Give larger units precedence over smaller ones as much as possible (e.g., return 2 min, 10 sec and not 1 min, 70 sec or 130 sec) Mimic the formatting shown in the test-cases (quantities sorted from largest unit to smallest and separated by comma+space; value and unit of each quantity separated by space).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Convert seconds to compound duration step by step in the Julia programming language
The Julia source code provided defines a function called duration
that takes an integer representing the number of seconds as input and returns a string representing the duration in a human-readable format. Here's how this code works:
-
Initialization: The function initializes an empty array
t
of typeArray{Int, 1}
. This array will be used to store the values for weeks, days, hours, minutes, and seconds. -
Loop Through Units: The code then enters a loop that iterates through the following units in descending order: weeks, days, hours, minutes, and seconds. The loop uses the
for
comprehension to generate a sequence of tuples(divisor, unit)
wheredivisor
is the number of seconds in the unit andunit
is the corresponding unit abbreviation. -
Dividing by Units: Inside the loop, it performs the following operations:
- Divides the input
sec
by the current divisor, storing the remainder inm
. This effectively computes the number of complete units (e.g., weeks, days, hours) elapsed within the total duration. - Updates
sec
to the remaining seconds after accounting for the current unit. - Pushes the computed
m
value as the first element of thet
array.
- Divides the input
-
Push Last Element: After the loop completes, it pushes the final value of
sec
, representing the remaining seconds, as the first element oft
. -
Construct Result String: The code then constructs a string by iterating through the
t
array and zip-combining it with theunit
array. For each pair of(num, unit)
in the result, it constructs a string in the format"$num$unit"
(e.g., "1w", "2d") but only includes the strings wherenum
is greater than 0 (to avoid displaying zero units). -
Join and Return: Finally, it joins all the non-zero duration strings together using commas and returns the result string.
Example Usages:
After defining the duration
function, the code includes several @show calls to demonstrate its usage:
@show duration(7259)
: This call displays the duration string for 7259 seconds, which is approximately "2h 1m 19s".@show duration(86400)
: This call shows the duration string for 86400 seconds, which is equivalent to a day and is displayed as "1d".@show duration(6000000)
: This call showcases the duration string for 6000000 seconds, which is roughly 69 days and is displayed as "1w 5d 5h 46m 40s".
Source code in the julia programming language
# 1.x
function duration(sec::Integer)::String
t = Array{Int}([])
for dm in (60, 60, 24, 7)
sec, m = divrem(sec, dm)
pushfirst!(t, m)
end
pushfirst!(t, sec)
return join(["$num$unit" for (num, unit) in zip(t, ["w", "d", "h", "m", "s"]) if num > 0], ", ")
end
@show duration(7259)
@show duration(86400)
@show duration(6000000)
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