How to resolve the algorithm Convert seconds to compound duration step by step in the PL/I programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Convert seconds to compound duration step by step in the PL/I programming language
Table of Contents
Problem Statement
Write a function or program which: This is detailed below (e.g., "2 hr, 59 sec").
Demonstrate that it passes the following three test-cases: Test CasesDetailsThe following five units should be used: However, only include quantities with non-zero values in the output (e.g., return "1 d" and not "0 wk, 1 d, 0 hr, 0 min, 0 sec"). Give larger units precedence over smaller ones as much as possible (e.g., return 2 min, 10 sec and not 1 min, 70 sec or 130 sec) Mimic the formatting shown in the test-cases (quantities sorted from largest unit to smallest and separated by comma+space; value and unit of each quantity separated by space).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Convert seconds to compound duration step by step in the PL/I programming language
Source code in the pl/i programming language
/* Convert seconds to Compound Duration (weeks, days, hours, minutes, seconds). */
cvt: procedure options (main); /* 5 August 2015 */
declare interval float (15);
declare (unit, i, q controlled) fixed binary;
declare done bit (1) static initial ('0'b);
declare name (5) character (4) varying static initial (' wk', ' d', ' hr', ' min', ' sec' );
get (interval);
put edit (interval, ' seconds = ') (f(10), a);
if interval = 0 then do; put skip list ('0 sec'); stop; end;
do unit = 60, 60, 24, 7;
allocate q;
q = mod(interval, unit);
interval = interval / unit;
end;
allocate q; q = interval;
do i = 1 to 5;
if q > 0 then
do;
if done then put edit (', ') (a);
put edit (trim(q), name(i)) (a, a); done = '1'b;
end;
if i < 5 then free q;
end;
end cvt;
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