How to resolve the algorithm Convert seconds to compound duration step by step in the uBasic/4tH programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Convert seconds to compound duration step by step in the uBasic/4tH programming language

Table of Contents

Problem Statement

Write a function or program which: This is detailed below (e.g., "2 hr, 59 sec").

Demonstrate that it passes the following three test-cases: Test CasesDetailsThe following five units should be used: However, only include quantities with non-zero values in the output (e.g., return "1 d" and not "0 wk, 1 d, 0 hr, 0 min, 0 sec"). Give larger units precedence over smaller ones as much as possible (e.g., return 2 min, 10 sec and not 1 min, 70 sec or 130 sec) Mimic the formatting shown in the test-cases (quantities sorted from largest unit to smallest and separated by comma+space; value and unit of each quantity separated by space).

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Convert seconds to compound duration step by step in the uBasic/4tH programming language

Source code in the ubasic/4th programming language

Proc _CompoundDuration(7259)
Proc _CompoundDuration(86400)
Proc _CompoundDuration(6000000)

End


_CompoundDuration Param(1)             ' Print compound seconds
  a@ = FUNC(_Compound(a@, 604800, _wk))
  a@ = FUNC(_Compound(a@, 86400, _d))
  a@ = FUNC(_Compound(a@, 3600, _hr))
  a@ = FUNC(_Compound(a@, 60, _min))

  If a@ > 0 Then Print a@;" sec";      ' Still seconds left to print?
  Print
Return


_Compound Param(3)
  Local(1)

  d@ = a@/b@                           ' Get main component
  a@ = a@%b@                           ' Leave the rest

  If d@ > 0 Then                       ' Print the component
    Print d@;
    Proc c@

    If a@ > 0 Then
      Print ", ";                      ' If something follows, take
    EndIf                              ' care of the comma
  EndIf
Return (a@)


_wk  Print " wk";  : Return
_d   Print " d";   : Return
_hr  Print " hr";  : Return
_min Print " min"; : Return


  

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