How to resolve the algorithm Count in factors step by step in the Forth programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Count in factors step by step in the Forth programming language
Table of Contents
Problem Statement
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors. For the purpose of this task, 1 (unity) may be shown as itself.
2 is prime, so it would be shown as itself. 6 is not prime; it would be shown as
2 × 3
{\displaystyle 2\times 3}
. 2144 is not prime; it would be shown as
2 × 2 × 2 × 2 × 2 × 67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count in factors step by step in the Forth programming language
Source code in the forth programming language
: .factors ( n -- )
2
begin 2dup dup * >=
while 2dup /mod swap
if drop 1+ 1 or \ next odd number
else -rot nip dup . ." x "
then
repeat
drop . ;
: main ( n -- )
." 1 : 1" cr
1+ 2 ?do i . ." : " i .factors cr loop ;
15 main bye
You may also check:How to resolve the algorithm SHA-256 step by step in the AWK programming language
You may also check:How to resolve the algorithm CSV to HTML translation step by step in the AutoIt programming language
You may also check:How to resolve the algorithm Multi-base primes step by step in the Go programming language
You may also check:How to resolve the algorithm Grayscale image step by step in the Factor programming language
You may also check:How to resolve the algorithm Split a character string based on change of character step by step in the C programming language