How to resolve the algorithm Count in factors step by step in the Run BASIC programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Count in factors step by step in the Run BASIC programming language
Table of Contents
Problem Statement
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors. For the purpose of this task, 1 (unity) may be shown as itself.
2 is prime, so it would be shown as itself. 6 is not prime; it would be shown as
2 × 3
{\displaystyle 2\times 3}
. 2144 is not prime; it would be shown as
2 × 2 × 2 × 2 × 2 × 67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count in factors step by step in the Run BASIC programming language
Source code in the run programming language
for i = 1000 to 1016
print i;" = "; factorial$(i)
next
wait
function factorial$(num)
if num = 1 then factorial$ = "1"
fct = 2
while fct <= num
if (num mod fct) = 0 then
factorial$ = factorial$ ; x$ ; fct
x$ = " x "
num = num / fct
else
fct = fct + 1
end if
wend
end function
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