Step by Step solution about How to resolve the algorithm Count in octal step by step in the C programming language

This C code demonstrates an infinite loop using a do-while statement and the octal (base-8) representation of an unsigned integer. A step-by-step explanation of the code:

1. Header Inclusion:

   • #include <stdio.h>: This line includes the standard input/output library, which provides functions like printf.

2. Main Function:

   • The main function is the entry point of the program.

3. Variable Declaration:

   • unsigned int i = 0;: Declares an unsigned integer variable i and initializes it to 0.

4. do-while Loop:

   • do { ... } while(i);: This is an infinite loop. The block inside the do statement will execute at least once before checking the condition in the while statement.
   • printf("%o\n", i++);: Inside the loop, it prints the octal value of i followed by a newline using the %o format specifier. Then, it increments i by 1.

5. Loop Condition:

   • while(i): The loop continues as long as i is non-zero. However, since i is incremented each time, it will eventually wrap around to 0 due to the overflow behavior of unsigned integers, causing the loop to terminate.

6. Return Statement:

   • return 0;: This statement indicates the successful execution of the program and is typically returned by the main function in C programs.

In summary, this code sets up an infinite loop that prints the octal representation of an unsigned integer i starting from 0. However, since i is unsigned, it will wrap around to 0 after reaching its maximum value, effectively terminating the loop.

#include <stdio.h>

int main()
{
        unsigned int i = 0;
        do { printf("%o\n", i++); } while(i);
        return 0;
}