How to resolve the algorithm Count in octal step by step in the Elixir programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Count in octal step by step in the Elixir programming language

Table of Contents

Problem Statement

Produce a sequential count in octal,   starting at zero,   and using an increment of a one for each consecutive number. Each number should appear on a single line,   and the program should count until terminated,   or until the maximum value of the numeric type in use is reached.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Count in octal step by step in the Elixir programming language

Source code in the elixir programming language

Stream.iterate(0,&(&1+1)) |> Enum.each(&IO.puts Integer.to_string(&1,8))


Stream.unfold(0, fn n ->
  IO.puts Integer.to_string(n,8)
  {n,n+1}
end) |> Stream.run


f = fn ff,i -> :io.fwrite "~.8b~n", [i]; ff.(ff, i+1) end
f.(f, 0)


  

You may also check:How to resolve the algorithm XML/XPath step by step in the AArch64 Assembly programming language
You may also check:How to resolve the algorithm Fusc sequence step by step in the Ring programming language
You may also check:How to resolve the algorithm Mutex step by step in the M2000 Interpreter programming language
You may also check:How to resolve the algorithm Loops/N plus one half step by step in the AWK programming language
You may also check:How to resolve the algorithm Check input device is a terminal step by step in the Racket programming language