How to resolve the algorithm Count in octal step by step in the Elixir programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Count in octal step by step in the Elixir programming language
Table of Contents
Problem Statement
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number. Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count in octal step by step in the Elixir programming language
Source code in the elixir programming language
Stream.iterate(0,&(&1+1)) |> Enum.each(&IO.puts Integer.to_string(&1,8))
Stream.unfold(0, fn n ->
IO.puts Integer.to_string(n,8)
{n,n+1}
end) |> Stream.run
f = fn ff,i -> :io.fwrite "~.8b~n", [i]; ff.(ff, i+1) end
f.(f, 0)
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